Question

我有一个选择框，具有两个字段组合值作为单个选项例如：name1（name1_code），name2（name2_code）并从ajax调用响应中填充此值。我有一个用于提交表单和编辑页面的表单。如果我有$id，我想在选择框中填充值。我尝试过

js code
$.each(data, function(key, value) {     //populate value 
   $('#project_name').append($("<option></option>")
   .text(value).attr("value",key)); 
});

Php

if(isset($id))          
{
 $types=DB::table('sow_mapping as m')->leftJoin('sow as s','m.sow_id','=','s.id')->leftJoin('project as p','p.id','=','m.project_id')->where('p.code','=',$asset_request->project_code)->pluck('s.number','s.code')->all();
 $sow_code=db::table('sow')->where('code',$asset_request->sow)->value('number');
 echo Form::select('sow_name',
    [''=>'Select']+$types,$asset_request->sow.'('.$sow_code.')',['class'=>'selectpicker default','id'=>'sow_name']);
 }



print_r($types) output as 
   Array ( [SOW_1395] => WJT - SOW 07 ) 

 I want to print as  `SOW_1395(WJT - SOW 07)`

是否可以打印为SOW_1395(WJT - SOW 07)

Answer 1

您可以将键附加值

$.each(data, function(key, value) {     //populate value 
   $('#project_name').append($("<option></option>")
   .text(key+'('+value+')').attr("value",key)); 
});

laravel视图页面中的selectbox组合值

1 个答案: