Question

这可能是一个简单的SQL语句，但是现在我有一个“大脑冻结”。

我有这张桌子

variant_id | filter_id
1585593211       4
1585593211       48
1585593212       4
1585593212       49

我需要获取具有filters_id：4和48的variant_id。在这种情况下，我希望获得1585593211

Answer 1

您可以使用IN来获取filter_id 4或48的所有行。然后GROUP BY variant_id并检查filter_id子句中不同的HAVING的计数是否等于2。

SELECT variant_id
       FROM elbat
       WHERE filter_id IN (4, 48)
       GROUP BY variant_id
       HAVING count(DISTINCT filter_id) = 2;

Answer 2

这是一个“套内查询”

您可以尝试根据条件获得count，然后找到variant_id个计数等于2

模式（MySQL v5.6）

CREATE TABLE T(
   variant_id INT,
   filter_id INT
);


INSERT INTO T VALUES (1585593211,4);
INSERT INTO T VALUES (1585593211,48);
INSERT INTO T VALUES (1585593212,4);
INSERT INTO T VALUES (1585593212,49);

查询＃1

SELECT variant_id
FROM T t1
where filter_id in (4,48)
group by variant_id
HAVING COUNT(*) = 2;

| variant_id |
| ---------- |
| 1585593211 |

View on DB Fiddle

或

select variant_id
from T
group by variant_id
having sum(filter_id = 4) > 0 and 
       sum(filter_id = 48) > 0

Answer 3

SELECT variant_id
FROM TABLENAME where filter_id in (4,48) group by variant_id having count(distinct filter_id)>1;

group by，其中filter_id将过滤具有4和48的所有数据特定的变体ID。但是当我们添加
时，将满足实际要求 having count(distinct filter_id)>1;
这样可以确保filter_id中同时有和 4和48 。

多行SQL where语句

3 个答案: