Question

我需要编写一个C程序，该程序将计算在命令行上声明的每个文件中的单词数量。我专门为每个文件创建一个进程，然后读取该文件中的单词数量，父进程需要等待并打印出总数。这是我的代码：

1 #include <stdio.h>
2 #include <stdlib.h>
3 #include <errno.h>
4
5 int main(int argc, char *argv[])
6 {
7         int i;
8         int pid;
9         int total_ammount_of_words;
10         FILE *current_file;
11
12         //Create processes for each file on the command line
13         for(i = 1; i < argc; i++)
14         {
15                 pid = fork();
16                 if(pid == -1) //Error
17                 {
18                         exit(-1);
19                 }
20                 else if(pid == 0) //Children
21                 {
22                         current_file = fopen(argv[i], "r");
23                         total_ammount_of_words += countWords(current_file);
24                         printf("Child Process for File %s: number of words is: %i\n", argv[i], c    ountWords(current_file));
25                         exit(0);
26                 }
27                 else //Parent
28                 {
29                         wait(NULL);
30                 }
31
32         }
33         printf("All %i files have been counted!\n Total Ammount of Words: %i\n", (argc-1), total    _ammount_of_words);
34
35 }
36
37 int countWords(FILE *file){
38         int count = 0;
39         char character;
40         while((character = fgetc(file)) != EOF){
41                 if(character == '\n' || character == ' ')
42                         count++;
43         }
44         return count;
45 }

这是我在命令行上声明的内容（每个文件中只有一个字，因此我的输出应等于3）：

assign1 cat.txt dog.txt fish.txt

我不明白为什么我一直把这个作为输出：

Child Process for File cat.txt: number of words is: 0
Child Process for File dog.txt: number of words is: 0
Child Process for File fish.txt: number of words is: 0
All 3 files have been counted!
Total Amount of Words: 32767

我不明白为什么我的代码没有正确计算单词数量？我用谷歌搜索已经计算了文件中所有单词的其他人，并且我完全按照它们来做。

C程序计算每个文件中的单词数

0 个答案: