Question

Ubuntu 16.04
重击4.3.3

如果第六列中不存在逗号，我还需要一种在逗号后添加空格的方法。我不得不注释上面的行，因为它在csv文件中的所有逗号之后放置了一个空格。

错误： "This is 6th column,Hey guys,Red White & Blue,I know it,Right On"

完美： "This is 6th column, Hey guys, Red White & Blue, I know it, Right On"

我几乎可以看到awk打印出第六列，然后让sed进行其余操作：

awk '{ print $6 }' "$feed " | sed -i 's/|/,/g; s/,/, /g; s/,\s\+/, /g'

这是我到目前为止所拥有的：

for feed in *; do
   sed -r -i 's/([^,]{0,10})[^,]*/\1/5' "$feed"
   sed -i '
      s/<b>//g; s/*//g;
      s/\([0-9]\)""/\1inch/g;
#     s/|/,/g; s/,/, /g; s/,\s\+/, /g;
      s/"one","drive"/"onetext","drive"/;
      s/"comments"/"description"/;
      s/"features"/"optiontext"/;
    ' "$feed"
done

s/|/,/g; s/,/, /g; s/,\s\+/, /g;有效，但它是全局的，不在列内。

Answer 1

听起来您需要的就是这个（将GNU awk用于FPAT）：

awk 'BEGIN{FPAT="[^,]*|\"[^\"]+\""; OFS=","} {gsub(/, ?/,", ",$6)} 1'

例如：

$ cat file
1,2,3,4,5,"This is 6th column,Hey guys,Red White & Blue,I know it,Right On",7,8

$ awk 'BEGIN{FPAT="[^,]*|\"[^\"]+\""; OFS=","} {gsub(/, ?/,", ",$6)} 1' file
1,2,3,4,5,"This is 6th column, Hey guys, Red White & Blue, I know it, Right On",7,8

实际上看起来您的整个shell脚本（包括对GNU sed的多次调用）只需一次对GNU awk的调用就可以更有效地完成，而无需围绕shell循环，例如（未试用）：

awk -i inplace '
BEGIN{FPAT="[^,]*|\"[^\"]+\""; OFS=","} 
{
    $0 = gensub(/([^,]{0,10})[^,]*/,"\\1",5)
    $0 = gensub(/([0-9])""/,"\\1inch","g")
    sub(/"one","drive"/,"\"onetext\",\"drive\"")
    sub(/"comments"/,"\"description\"")
    sub(/"features"/,"\"optiontext\"")
    gsub(/, ?/,", ",$6)
}
' *

如果csv文件第6列中没有逗号，如何在逗号后添加空格？

1 个答案: