Question

当我运行时，它将转到名为niceJob.txt的文件，数据来自的文件名为file2.txt，其中包含

niceJob.txt 40
20 1 1 5 7 45 1 2 3 4 5 6 7 8 9 77 88 99 23 34 56

当我打开niceJob.txt时，它将显示

X8

我真的对为什么以及如何发生感到困惑。这是代码：

import java.io.*;
import java.util.Scanner;

public class JH1_00668860 {
    public static void printToScreen(String filename) {
        Scanner scan = null;
        try {
            FileInputStream fis = new FileInputStream(filename);
            scan = new Scanner(fis);
            while (scan.hasNextLine()) {
                System.out.println(scan.nextLine());
            }
        } catch (FileNotFoundException e) {
            System.out.println("printToScreen: can't open: " + filename);
        } finally {
            if (scan != null)
                scan.close();
        }
    }// end of print

    public static void process(String inputFilename) {
        String fileoutputname = null;
        FileInputStream file = null;
        Scanner scan = null;
        FileOutputStream outputFilename = null;
        FileWriter ps = null;
        try {
            file = new FileInputStream(inputFilename);
            scan = new Scanner(file);
            fileoutputname = scan.next();
            System.out.println(fileoutputname + "      asfasdfasdfasdf");

            outputFilename = new FileOutputStream(fileoutputname);
            ps = new FileWriter(fileoutputname);
            while (scan.hasNextInt()) {
                if (scan.nextInt() >= 0) {
                    // System.out.println(scan.nextInt() + "asfs");
                    ps.write(scan.nextInt());
                    ps.flush();

                } else {
                    System.out.println("You have ran out of data or you have a bad value");
                }
            }

            System.out.println("A file was created");
        } catch (FileNotFoundException e) {
            System.out.println("You ran into an exception :" + e);
        } catch (IOException e) {
            System.out.println("You ran into an exception :" + e);

        } finally {
            try {
                if (file != null) {
                    file.close();

                }
                if (outputFilename != null) {
                    outputFilename.close();

                }
                if (ps != null) {
                    ps.close();

                }
                // FileInputStream st = new FileInputStream(fileoutputname);
                // int contents = st.read();
                // while (scan.hasNextInt()) {
                // System.out.print(contents);
                // }
                if (scan != null) {
                    scan.close();
                }


                printToScreen(fileoutputname);

            } catch (IOException e) {
                System.out.println("there was an exception");
            }

        }

    }

    public static void main(String args[]) {
        process("file2.txt");

    }
}

Answer 1

您正在scan.nextInt()循环中多次调用while（两次），并使用第二次调用scan.nextInt()来写入文件ps.write(scan.nextInt())；它会跳过每一个备用integer

您将integer传递给ps.write()，而传递string

import java.util.Scanner;
import java.io.*;


public class Main {
    public static void printToScreen(String filename) {
        Scanner scan = null;
        try {
            FileInputStream fis = new FileInputStream(filename);
            scan = new Scanner(fis);
            while (scan.hasNextLine()) {
                System.out.println(scan.nextLine());
            }
        } catch (FileNotFoundException e) {
            System.out.println("printToScreen: can't open: " + filename);
        } finally {
            if (scan != null)
                scan.close();
        }
    }// end of print

    public static void process(String inputFilename) {
        String fileoutputname = null;
        FileInputStream file = null;
        Scanner scan = null;
        FileOutputStream outputFilename = null;
        FileWriter ps = null;
        try {
            file = new FileInputStream(inputFilename);
            scan = new Scanner(file);
            fileoutputname = scan.next();
            System.out.println(fileoutputname + "      asfasdfasdfasdf");

            outputFilename = new FileOutputStream(fileoutputname);
            ps = new FileWriter(fileoutputname);
            int currentInt = -1;
            while (scan.hasNextInt()) {
                currentInt = scan.nextInt();
                if (currentInt >= 0) {
                    //System.out.println(currentInt + "asfs");
                    ps.write(String.valueOf(currentInt));
                    ps.flush();

                } else {
                    System.out.println("You have ran out of data or you have a bad value");
                }
            }

            System.out.println("A file was created");
        } catch (FileNotFoundException e) {
            System.out.println("You ran into an exception :" + e);
        } catch (IOException e) {
            System.out.println("You ran into an exception :" + e);

        } finally {
            try {
                if (file != null) {
                    file.close();

                }
                if (outputFilename != null) {
                    outputFilename.close();

                }
                if (ps != null) {
                    ps.close();

                }
                // FileInputStream st = new FileInputStream(fileoutputname);
                // int contents = st.read();
                // while (scan.hasNextInt()) {
                // System.out.print(contents);
                // }
                if (scan != null) {
                    scan.close();
                }


                printToScreen(fileoutputname);

            } catch (IOException e) {
                System.out.println("there was an exception");
            }

        }

    }

    public static void main(String args[]) {
        process("sample.txt");

    }
}

输出：

niceJob.txt      asfasdfasdfasdf
A file was created
4020115745123456789778899233456

编写者为什么不将数据写入文件？

1 个答案: