所以我有一个字符串，我需要找到匹配两个约束的单词，即单词中的字符数应该是偶数，并且应该是最长的单词。
例如：
Input: I am a bad coder with good logical skills
Output: skills
只需从R开始，那么任何帮助都会很棒。
答案 0 :(得分：2)
您可以尝试使用库import React, { Component } from "react";
import axios from "axios";
import moment from "moment";
export default class Feutred extends Component {
state = {
sports: [],
events: [],
isLoading: true,
errors: null
};
getSports() {
axios
.get("/api/v1/sports.json")
.then(response =>
response.data.map(sport => ({
id: sport.id,
name: sport.name,
slug: sport.slug
}))
)
.then(sports => {
this.setState({
sports,
isLoading: false
});
})
.catch(error => this.setState({ error, isLoading: false }));
}
getEvents() {
axios
.get("/api/v1/events?sport_id=${sport_id}")
.then(response =>
response.data.map(event => ({
id: event.id,
time: event.time,
league: event.league,
time_status: event.time_status,
homeTeam: event.home,
awayTeam: event.away
}))
)
.then(events => {
this.setState({
events,
isLoading: false
});
})
.catch(error => this.setState({ error, isLoading: false }));
}
componentDidMount() {
this.getSports();
(this.interval = setInterval(
() => this.getEvents({ time: Date.now() }),
12000
));
}
componentWillUnmount() {
clearInterval(this.interval);
}
render() {
const { sports, isLoading } = this.state;
return (
<React.Fragment>
{!isLoading ? (
sports.map(sport => {
const { id, name } = sport;
return (
<div key={sport.id}>
<div className="text">
<p className="meta">
<span className="matchinfo">
<span className="block">time</span>
<span className="block">timestatus</span>
</span>
</p>
<h3>
<a href="">home-team vs aya tream</a>
</h3>
<p className="league">
<a className="watchlive" href="">
<span className="icon" />
<span>Watch live</span>
</a>
<span>{sport.name} - league cc - league name</span>
</p>
</div>
</div>
);
})
) : (
<p>Loading...</p>
)}
</React.Fragment>
);
}
}
tokenizers答案 1 :(得分：0)
这是我的代码：
input<-"I am a bad coder with good logical skills"
words<-strsplit(input," ") # Split it to words
countWords<-sapply(words,nchar) # Count the length of words
dt<-data.frame( word=unlist(words), length=unlist(countWords) ) # Make a dataframe
dt<-dt[order(dt$length),] # Sort the dataframe based on length
dt<-dt[ which((dt$length %% 2)==1),] # Get the words with odd length
dt[nrow(dt),] # Get the longest word