Question

使用这两个正则表达式regPrefix和regSuffix，

final String POEM = "1. Twas brillig, and the slithy toves\n" + 
                    "2. Did gyre and gimble in the wabe.\n" +
                    "3. All mimsy were the borogoves,\n" + 
                    "4. And the mome raths outgrabe.\n\n";

String regPrefix = "(?m)^(\\S+)";   // for the first word in each line.
String regSuffix = "(?m)\\S+\\s+\\S+\\s+\\S+$";  // for the last 3 words in each line.
Matcher m1 = Pattern.compile(regPrefix).matcher(POEM);
Matcher m2 = Pattern.compile(regSuffix).matcher(POEM);

while (m1.find() && m2.find()) {
    System.out.println(m1.group() + " " + m2.group());
}

我得到的正确输出为：

1. the slithy toves
2. in the wabe.
3. were the borogoves,
4. mome raths outgrabe.

是否可以将这两个正则表达式表达式合并为一个，并获得相同的输出？我尝试过类似的事情：

String singleRegex = "(?m)^(\\S+)\\S+\\s+\\S+\\s+\\S+$";

但这对我不起作用。

Answer 1

使用具有两个捕获组的单个模式：

String regex = "(?m)^(\\S+).*?((?:\\s+\\S+){3})$";
Matcher m = Pattern.compile(regex).matcher(POEM);
while (m.find()) {
    System.out.println(m.group(1) + m.group(2));
}

1. the slithy toves
2. in the wabe.
3. were the borogoves,
4. mome raths outgrabe.

使用正则表达式

1 个答案:

Demo