list = [c,a,r,p,e,t]
function reverse(list) {
var i =0; j= list.length-1;
while(i < j) {
var temp = list[i];
list[i] = list[j];
list[j] = temp;
i++;
j--;
}
return list;
}
大家好,我正在尝试解决上述问题。它适用于数字数组。如何调整它以处理字符列表?
答案 0 :(得分:2)
数组可以通过设计反转,而无需循环:
var list = ['c','a','r','p','e','t'];
var reversedList = list.slice(0).reverse();
检查Mozilla Developer Network: Array.prototype.reverse()和Mozilla Developer Network: Array.prototype.slice()以获得更多信息。
答案 1 :(得分:0)
只需使用.reverse();
并假设c,a,r,p,e,t
是变量,然后使用String()
如果要按字母排序,则使用Number()
如果按数字排序。
按字符串排序:
var list = [String(c),String(a),String(r),String(p),String(e),String(t)].reverse();
按数字排序:
var list = [Number(c),Number(a),Number(r),Number(p),Number(e),Number(t)].reverse();
答案 2 :(得分:0)
您的代码引发-未捕获的ReferenceError:c未定义。当您错过将“或'与字符一起放置时。
更改步骤数组声明步骤:
来自:列表= [c,a,r,p,e,t] 到:list = ['c','a','r','p','e','t'] 或 list = [“ c”,“ a”,“ r “,” p“,” e“,” t“]
您的工作代码
$args= array(
'post_type' => array( 'post', 'case-study' ),
's' => $search_term
);
jsfiddle工作示例:
https://jsfiddle.net/m6kt3eus/1/
实现此目标的其他更简单方法: 反转数组的简单方法是javascript中的reverse()
下面是示例代码段:
import java.text.Collator;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
import java.util.Locale;
public class CountryList {
public static List<Country> get() {
// A collection to store our country object
List<Country> countries = new ArrayList<Country>();
// Get ISO countries, create Country object and
// store in the collection.
String[] isoCountries = Locale.getISOCountries();
for (String country : isoCountries) {
Locale locale = new Locale("en", country);
String iso = locale.getISO3Country();
String code = locale.getCountry();
String name = locale.getDisplayCountry();
if (!"".equals(iso) && !"".equals(code) && !"".equals(name)) {
countries.add(new Country(iso, code, name));
}
}
// Sort the country by their name and then display the content
// of countries collection object.
Collections.sort(countries, new CountryComparator());
return countries;
}
/**
* Country pojo class.
*/
public static class Country {
private String iso;
private String code;
private String name;
Country(String iso, String code, String name) {
this.iso = iso;
this.code = code;
this.name = name;
}
public String toString() {
return iso + " - " + code + " - " + name.toUpperCase();
}
}
/**
* CountryComparator class.
*/
private static class CountryComparator implements Comparator<Country> {
private Comparator<Object> comparator;
CountryComparator() {
comparator = Collator.getInstance();
}
public int compare(Country c1, Country c2) {
return comparator.compare(c1.name, c2.name);
}
}
}
arr.reverse()用于数组的原位反转。数组的第一个元素变为最后一个元素,反之亦然。
语法:
var list = ['c','a','r','p','e','t'];
function reverse(list) {
var i =0; j= list.length-1;
while(i < j) {
var temp = list[i];
list[i] = list[j];
list[j] = temp;
i++;
j--;
}
return list;
}
//Call the method;
reverse(list);
参数 此函数不带任何参数。
返回值 此函数返回反转的原始数组的引用。
答案 3 :(得分:0)
function reverse(list) {
var list2 = [];
for (let i = 0; i < list.length; i++)
list2.unshift(list[i]);
return list2;
}
var list = ['c', 'a', 'r', 'p', 'e', 't'];
console.log(reverse(list));