Question

def keti():
    if payf=="y":
        print("The fees are {}".format(amount))
        if payf == "n":
            amount = amount +10
            print ("the fees are {}".format (amount ))

def keti2():
    if payf=="y":
        amount =2*amount
        print("The fees are {}".format(amount))
        if payf == "n":
            amount =2*amount
            amount = amount +10
            print ("the fees are {}".format (amount ))

ket=int(input("no of kts"))
print(ket)
payf = str(input("hav u paid"))
print (payf)
amount=250
if (ket=="1"):
    keti()
elif (ket=="2"):
    keti2 ()
else:
    print ("wrong input")

这有什么问题？每次执行其他语句我不明白这是怎么回事

Answer 1

ket=int(input("no of kts"))     # you have converted ket into int object 
print(ket)
if (ket=="1"):                   # here your trying to compare an int object and string object ,try it with ket==1 or ket==int("1")
    keti()
elif (ket=="2"):
    keti2 ()
else:
    print ("wrong input")

您正在将int对象与字符串进行比较，请尝试如果ket == 1：

Answer 2

您已经将第一个输入转换为int，在这里：

ket = int(input("no of kts"))

因为它是整数，所以正确的比较应该是

if (ket == 1):
  ...
elif (ket == 2):
  ...

这段代码有什么问题？它不起作用！每次其他条件正常

2 个答案: