Question

当我对我的Web服务器进行GET api调用时，我得到以下响应。它正在返回值列表。我想遍历每个值并转换为Java对象“ Student”

[{
        "name": "xyz",
        "id": "1234"
    },
    {
        "name": "abc",
        "id": "1254"
}]

如何将列表中的每个值转换为具有两个字段“名称”和“ id”的java对象。

例如：-

class Student{

        String name;
        String id;

    }

Answer 1

您可以使用Gson。它解析对给定（兼容）Java对象的Json响应：

GsonBuilder builder = new GsonBuilder();
jsonObject = builder.create().fromJson(jsonString, jsonObject.class);

class jsonObject {
    ArrayList<Student> students;

    class Student {
        String name;
        String id;
    }
}

jsonString是您的API响应。由于响应是学生对象的列表，因此您需要将学生对象包装到类似这样的列表中。

Answer 2

在获得Api响应的地方添加此代码

//make both string id and name public in your Student class
ArrayList<Student> students;
try{
 Student student=new Student();
 JSONObject jsonObject = new JSONObject(response);//adding all response in JSON
students=new ArrayList<>();
 //the loop will run as many times as the object in the response.In this case loop will run two times
 for(i=0;i<jsonObjest.length;i++){
     JSONObject jsonString = jsonObjest.getJSONObject(i);//here getting all object by index 
     //adding data 
     student.id=jsonString.getString("id");
     student.name=jsonString.getString("name");
     students.add(student);//adding all data in arraylist.Now if you want to diplay this all data by listView...You new need to just pass this "students" ArrayList in your adapter 
 }  

}catch(JSONException e) {
  Log.d("===",""Exception::  "+e.getMassege());

}

将返回值列表的API响应转换为JavaObject

2 个答案: