我正在尝试在Swift中实现这一目标:
let dict : [ () -> () : String]
//error: type '() -> ()' does not conform to protocol 'Hashable'
//let dict : [ () -> () : String]
//^
但是出现错误'()->()'不符合协议'Hashable'。我该如何解决该错误?
编辑: 我正在从Lua移植有限状态机,而键恰好是一个函数。 (我知道用其他任何语言都可能很奇怪,但是对于Lua来说还可以)。 Lua代码:
local machine = {}
machine [Entry] = {loop = Entry, go = Another, gosub = sub }
machine [Another] = {go = Entry, loop = Another, next = Next }
machine [Next] = {startAgain = Entry }
machine [sub] = {out = Entry, next = Next, gosub = indoor, goOutDoor = outdoor }
machine [indoor] = {out = sub, next = sub }
machine [outdoor] = {next = sub }
答案 0 :(得分:1)
我认为您不能修复它。字典的密钥必须符合2018_06_02_023820_create_role_user_table
协议。这意味着它具有Int hashValue属性,并且实现了Hashable
运算符。 (请参阅此链接:https://developer.apple.com/documentation/swift/hashable)
函数不符合==
协议,因此它们不能成为字典键。