Question

请参阅以下pprof会话。在treesort.add的第42行中，有一个int比较。我认为它占所有CPU时间的64％。灾难性地，该操作为“ MOVQ 0x30（SP），DX”。为什么这么慢？

File: treesort_bench.test.exe
Type: cpu
Time: Sep 7, 2018 at 3:15pm (EDT)
Duration: 2.60s, Total samples = 2.43s (93.44%)
Entering interactive mode (type "help" for commands, "o" for options)
(pprof) top 10
Showing nodes accounting for 2.41s, 99.18% of 2.43s total
Dropped 2 nodes (cum <= 0.01s)
      flat  flat%   sum%        cum   cum%
     2.40s 98.77% 98.77%      2.42s 99.59%  gopl.io/ch4/treesort.add
     0.01s  0.41% 99.18%      0.02s  0.82%  runtime.mallocgc
         0     0% 99.18%      0.26s 10.70%  gopl.io/ch4/treesort.Sort
         0     0% 99.18%      0.25s 10.29%  gopl.io/ch4/treesort_bench.BenchmarkSort
         0     0% 99.18%      0.26s 10.70%  gopl.io/ch4/treesort_bench.run
         0     0% 99.18%      0.02s  0.82%  runtime.newobject
         0     0% 99.18%      0.22s  9.05%  testing.(*B).launch
         0     0% 99.18%      0.02s  0.82%  testing.(*B).run1.func1
         0     0% 99.18%      0.25s 10.29%  testing.(*B).runN
(pprof) list add
Total: 2.43s
ROUTINE ======================== gopl.io/ch4/treesort.add in go\src\gopl.io\ch4\treesort\sort.go
     2.40s      4.45s (flat, cum) 183.13% of Total
         .          .     30:           values = appendValues(values, t.right)
         .          .     31:   }
         .          .     32:   return values
         .          .     33:}
         .          .     34:
      90ms       90ms     35:func add(t *tree, value int) *tree {
         .          .     36:   if t == nil {
         .          .     37:           // Equivalent to return &tree{value: value}.
         .       20ms     38:           t = new(tree)
         .          .     39:           t.value = value
         .          .     40:           return t
         .          .     41:   }
     1.55s      1.55s     42:   flag := value < t.value
         .          .     43:   if flag {
         .      240ms     44:           t.left = add(t.left, value)
         .          .     45:   } else {
     630ms      2.42s     46:           t.right = add(t.right, value)
         .          .     47:   }
     130ms      130ms     48:   return t
         .          .     49:}
         .          .     50:
         .          .     51://!-
(pprof) disasm add
Total: 2.43s
ROUTINE ======================== gopl.io/ch4/treesort.add
     2.40s      5.08s (flat, cum) 209.05% of Total
      50ms       50ms     4fcb66: MOVQ 0(AX), CX                          ;gopl.io/ch4/treesort.add sort.go:42
     1.48s      1.48s     4fcb69: MOVQ 0x30(SP), DX
      20ms       20ms     4fcb6e: CMPQ CX, DX
         .          .     4fcb71: JGE 0x4fcbbb                            ;sort.go:43

Answer 1

“ MOVQ 0x30（SP），DX”为什么变慢？

您提供的证据不足，无法证明教学进度缓慢。

MOVQ —移动四字-是来自Intel 64和IA-32体系结构指令集的一条指令。参见Intel® 64 and IA-32 Architectures Software Developer Manuals

tree.value指令将treesort_bench.test.exe变量的8个字节从内存移至DX寄存器。

与任何其他科学方法一样，性能测量也依赖于可重复的结果。您提供的信息不足，无法重现您的结果。例如，const: httpOptions = { ....... } export class SpringService { public getAllClubs(): any { return this.http.get(this.baseUrl+"/currentseason/get/clubs",httpOptions); } }的代码在哪里，什么处理器，什么内存，什么操作系统？

我已经尝试过，但是无法重现您的结果。添加您的代码和步骤以重现您的问题。

为什么“ MOVQ 0x30（SP），DX”变慢？

1 个答案: