Question

我正在Flask中编写一个API，该API接收用户详细信息并将其插入数据库中。我正在Android上使用Retrofit来使用此API。一切工作正常，但是用户输入值未以某种方式传递给API。数据库将使用空值而不是用户提供的值进行更新。

如果我使用邮递员在URL中手动添加参数值，则数据库确实会更新，即（主机名/ add_user？username =“ abc”＆password =“ abc” ....）

我是改造的新手，所以我不知道哪里出了问题！

烧瓶API：

@app.route('/add_user', methods=['POST'])
def add_user():

username    = request.args.get('username')
password    = request.args.get('password')
name        = request.args.get('name')
age         = request.args.get('age')
gender      = request.args.get('gender')
cnumber     = request.args.get('cnumber')
address     = request.args.get('address')
city_id     = request.args.get('city_id')
email       = request.args.get('email')

t   = (username,password,name,age,gender,cnumber,address,city_id,email) #Storing all the received values in tuple

cur = mysql.connection.cursor()

cur.execute("INSERT INTO users (username,password,name,age,gender,contactnumber,address,city_id,email) values (%s,%s,%s,%s,%s,%s,%s,%s,%s)", t)
    mysql.connection.commit()

    resp = jsonify("User added successfully")
    resp.status_code = 200
    resp.headers['Success'] = 'Success'

    return resp

JAVA代码：

Call<ResponseBody> call = API_Client.getInstance().getAPI().add_user(username.getText().toString(), password.getText().toString(), name.getText().toString(), Integer.parseInt(age.getText().toString()), gender.getSelectedItem().toString(), cnumber.getText().toString(), address.getText().toString(), city.getId(), email.getText().toString());
                    call.enqueue(new Callback<ResponseBody>() {
                        @Override
                        public void onResponse(Call<ResponseBody> call, Response<ResponseBody> response) {
                            try {
                                String s = response.body().string();
                                Toast.makeText(UserSignup.this, s, Toast.LENGTH_SHORT).show();

                            } catch (IOException e) {
                                e.printStackTrace();
                            }
                        }

                        @Override
                        public void onFailure(Call<ResponseBody> call, Throwable t) {

                            Toast.makeText(UserSignup.this, t.getMessage().toString(), Toast.LENGTH_SHORT).show();
                        }
                    });

API接口：

@FormUrlEncoded
@POST("add_user")
Call<ResponseBody> add_user(

        @Field("username") String username,
        @Field("password") String password,
        @Field("name") String name,
        @Field("age") int age,
        @Field("gender") String gender,
        @Field("cnumber") String cnumber,
        @Field("address") String address,
        @Field("city_id") int city_id,
        @Field("email") String email
);

}

Answer 1

我认为这必须是GET请求hostname/add_user?username="abc"&password="abc"。将您的API接口更改为此或仅将@Field替换为@Query

@GET("add_user")
Call<ResponseBody> add_user(

        @Query("username") String username,
        @Query("password") String password,
        @Query("name") String name,
        @Query("age") int age,
        @Query("gender") String gender,
        @Query("cnumber") String cnumber,
        @Query("address") String address,
        @Query("city_id") int city_id,
        @Query("email") String email
);

在Android上使用带有Retrofit的POST方法在MySQL中插入值

1 个答案: