获取前面的ID并继续查询的id

Question

我有一个功能可以获取特定ID的记录，并且有两个链接用于上一个和下一个记录。现在我有单独的查询来获取下一个id：

$query = "SELECT id FROM presentations WHERE id > '$getId' ORDER BY id ASC LIMIT 1";

$ getId是当前的ID。

有没有办法整合到一个查询中？

Answer 1

SELECT A.id AS previd, B.id AS nextid 
FROM 
  (SELECT id FROM presentations WHERE id < '$getId' ORDER BY id DESC LIMIT 1) A,  
  (SELECT id FROM presentations WHERE id > '$getId' ORDER BY id ASC LIMIT 1) B

返回2列：previd和nextid周围的$ getId

Answer 2

我认为你可以使用内部查询

SELECT id FROM presentations 
WHERE id >= ( SELECT id FROM presentations WHERE id < '$getId' ORDER BY id DESC LIMIT 0 , 1 ) 
ORDER BY id ASC LIMIT 0 , 3

第一个数组结果将是前一个记录，第二个将是您当前的记录，最后一个将是您的最后一个记录。