我正在尝试在EF Core类库中生成迁移,但到目前为止无济于事。我正在使用程序包管理器控制台(Visual Studio 2017社区)编写如下命令:
PM> Add-Migration Update37
但我总是收到错误消息:
无法创建类型为'DBContext'的对象。在项目中添加“ IDesignTimeDbContextFactory”的实现,或在设计时支持https://go.microsoft.com/fwlink/?linkid=851728的其他模式。
我的解决方案结构:
如您所见,我有2个项目,其中MesDBModels是类库,我要为其生成到Migrations文件夹的迁移。我添加了DummyProject
,以便在.NETcore运行时上提供“启动项目”。 DummyProject
还包含IDesignTimeDBContextFactory<>
类中DBContextFactory
接口的实现。此外,DummyProject
包含对MesDBModels
项目的引用。
MesDBModels.Database.DBContext:
using MesDBModels.FluentConfig;
using MesDBModels.Models;
using Microsoft.EntityFrameworkCore;
namespace MesDBModels.Database
{
public class DBContext : DbContext
{
public DBContext(DbContextOptions<DBContext> options) : base(options) { }
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.ApplyConfiguration(new AccessCardConfig());
modelBuilder.ApplyConfiguration(new AlarmConfig());
modelBuilder.ApplyConfiguration(new BitPositionConfig());
modelBuilder.ApplyConfiguration(new MachineConfig());
modelBuilder.ApplyConfiguration(new ParameterTemplateConfig());
modelBuilder.ApplyConfiguration(new ReferenceConfig());
modelBuilder.ApplyConfiguration(new ReferenceTemplateConfig());
modelBuilder.ApplyConfiguration(new UserConfig());
modelBuilder.ApplyConfiguration(new UserGroupConfig());
modelBuilder.ApplyConfiguration(new UserPermissionConfig());
base.OnModelCreating(modelBuilder);
}
public DbSet<AccessCard> AccessCards { get; set; }
public DbSet<Alarm> Alarms { get; set; }
public DbSet<AlarmDefinition> AlarmDefinitions { get; set; }
public DbSet<AlarmPriority> AlarmPriorities { get; set; }
public DbSet<BitPosition> BitPositions { get; set; }
public DbSet<EventLog> EventLogs { get; set; }
public DbSet<EventType> EventTypes { get; set; }
public DbSet<Group> Groups { get; set; }
public DbSet<Machine> Machines { get; set; }
public DbSet<MachineState> MachineStates { get; set; }
public DbSet<MachineStateDefinition> MachineStateDefinitions { get; set; }
public DbSet<Permission> Permissions { get; set; }
public DbSet<ParameterTemplate> ParameterTemplates { get; set; }
public DbSet<ReferenceParameterHistory> ReferenceParameterHistory { get; set; }
public DbSet<ParameterValueLimit> ParameterValueLimits { get; set; }
public DbSet<Reference> References { get; set; }
public DbSet<ReferenceParameterType> ReferenceParameterTypes { get; set; }
public DbSet<ReferenceTemplate> ReferenceTemplates { get; set; }
public DbSet<Session> Sessions { get; set; }
public DbSet<Unit> Units { get; set; }
public DbSet<UnitStatus> UnitStatuses { get; set; }
public DbSet<User> Users { get; set; }
public DbSet<UserGroup> UserGroups { get; set; }
public DbSet<UserPermission> UsersPermissions { get; set; }
}
}
DummyProject.DBContextFactory:
using Microsoft.EntityFrameworkCore;
using Microsoft.EntityFrameworkCore.Design;
namespace MesDBModels
{
public class DBContextFactory : IDesignTimeDbContextFactory<DbContext>
{
public DbContext CreateDbContext(string[] args)
{
var builder = new DbContextOptionsBuilder<DbContext>();
builder.UseSqlServer(
"Server=(local)\\serverName;Database=dbName;Trusted_Connection=True;MultipleActiveResultSets=true");
return new DbContext(builder.Options);
}
}
}
DummyProject.Program类:
using System;
namespace DummyProject
{
class Program
{
static void Main(string[] args)
{
Console.WriteLine("Hello World!");
}
}
}
所以我的问题是:我做错了什么?我试图将DBContextFactory
类和MesDBModels
类一起放在DBContext
项目中,但是结果是一样的。
我遵循了这个:
Using Entity Framework Core migrations for class library project
还有这个 :
https://garywoodfine.com/using-ef-core-in-a-separate-class-library-project/
但是,老兄,我误会了某件事或做错了什么。
请帮助。
答案 0 :(得分:0)
您在输入中有错字
public class DBContextFactory : IDesignTimeDbContextFactory<DbContext>
{
public DbContext CreateDbContext(string[] args)
{
var builder = new DbContextOptionsBuilder<DbContext>();
builder.UseSqlServer(
"Server=(local)\\serverName;Database=dbName;Trusted_Connection=True;MultipleActiveResultSets=true");
return new DbContext(builder.Options);
}
}
在尝试构造DBContext
时,框架会为IDesignTimeDbContextFactory
寻找DBContext
,但是您要为基础DbContext
实现一个工厂。在此代码中将DbContext
修改为DBContext
,它应该可以工作。