Question

下面有一个代码，用户可以在其中添加用,

分隔的英文文本数字

示例输入：三百三十五，六百一十五，三

输出应为： 335、6000501、3

下面是我的代码

print("Please type your number below")
value = input("")
string = ""
for unit_value in value.split(", "):
    string = str(challenge1(unit_value.lower()))   #function challenge1 code below (In my code it comes before )
    print(string)

我的输出如下为什么第一次循环后代码未运行

335             #I can switch the order no matter what number I put 1st it shows
None            #The 2nd and 3rd loop always show none no matter what the number 
None

我添加了打印语句，以查看是否一切正常，并且是

print("Please type your number below")
value = input("")
string = ""
for unit_value in value.split(", "):
    print(unit_value)   #extra print added to see unit_value
    string = str(challenge1(unit_value.lower()))
    print(unit_value)

output is correct as below 

three hundred thirty five
six million five hundred one
three

下面是功能Challenge1的详细信息

def challenge1(single_word, complete_number={}):
    if not complete_number:
        uniques = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve",
                   "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]


        teners = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"]

        big_nums = ["hundred", "thousand", "million"]    


        for index, word in enumerate(uniques):
            complete_number[word] = (1, index)
        for index, word in enumerate(teners):
            complete_number[word] = (1, index * 10)
        for index, word in enumerate(big_nums):
            complete_number[word] = (10 ** (index * 3 or 2), 0)


        current = 0
        result = 0

        for word in single_word.split():

            if word not in complete_number:
                print("Input is not a number. Please see the examples of how to enter number /n six  /n negative seven"
                      " hundred twenty nine, /n one million one hundred one")


            scale, increment = complete_number[word]
            current = current * scale + increment
            if scale > 100:
                result += current
                current = 0
     return result + current

Answer 1

编辑了函数，您需要清除（）字典，因为它是静态声明。您声明的字典是静态的，不会在每次调用时都重新创建，因此您需要清除它或像下面这样写：

def challenge1(single_word): 
   complete_number={}

更正的代码：

def challenge1(single_word, complete_number={}):
    if not complete_number:
        uniques = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve",
                   "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]


        teners = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"]

        big_nums = ["hundred", "thousand", "million"]

        negative = ["negative"]    

        for index, word in enumerate(uniques):
            complete_number[word] = (1, index)
        for index, word in enumerate(teners):
            complete_number[word] = (1, index * 10)
        for index, word in enumerate(big_nums):
            complete_number[word] = (10 ** (index * 3 or 2), 0)


        current = 0
        result = 0

        for word in single_word.split():

            if word not in complete_number:
                print("Input is not a number. Please see the examples of how to enter number /n six  /n negative seven"
                      " hundred twenty nine, /n one million one hundred one")


            scale, increment = complete_number[word]
            current = current * scale + increment
            if scale > 100:
                result += current
                current = 0
        complete_number.clear()
        return result + current

在python split function上运行forloop时出错

1 个答案: