Question

所以我必须这样做“打印测试分数，找到全班平均成绩，以及哪条成绩最好。”我很困惑

public class TESTAVG {

    public static void main(String[]args) {
        int array1[][] = {{90, 80, 65, 100}, {55, 94, 86,}, {82}, {77, 100}};
        System.out.println(array1);
    }
} //[[I@2a139a55

Answer 1

当需要对数组进行字符串化时，可以使用 Arrays.toString（arr）; 。对于多维数组，应使用Arrays.deepToString（arr）;。

int array1[][] = {{90, 80, 65, 100}, {55, 94, 86,}, {82}, {77, 100}};
System.out.println(Arrays.deepToString(array1));

[[90，80，65，100]，[55，94，86]，[82]，[77，100]]

Answer 2

要查找哪个子数组具有更大的平均值，必须计算它们并保持最大值：

public static void main(String[] args){
    int array1[][] = {{90, 80, 65, 100}, {55, 94, 86}, {82}, {77, 100}};
    double maxAverage = Double.MIN_VALUE;
    for(int[] sub : array1){                       //iterate over sub-arrays
        double average = averageOfArray(sub);      //compute its average
        maxAverage = Math.max(maxAverage, average);//get the max of it and the previous max
    }
    System.out.printn(maxAverage)
}

static double averageOfArray(int[] array){
    double sum = 0;
    for(int i=0; i<array.length; i++){
        sum += array[i];
    }   
    return sum/array.length;
}

或作为Java 8升级方式：

int array1[][] = {{90, 80, 65, 100}, {55, 94, 86,}, {82}, {77, 100}};
double maxAverage = Arrays.stream(array1).mapToDouble(sub -> Arrays.stream(sub).average().orElse(0)).max().orElse(0);
System.out.println(maxAverage)

最佳成绩阵列

2 个答案: