Question

下面是示例表：flg'E'表示现有，而'N'表示“新”。

LOC_RANK    b       c       d       rownum  flg
---------   ------  ------  ------  ------  ---
1           (null)  (null)  (null)  1       E
1           a       b       c       2       N
2           a       b       c       3       E
2           (null)  (null)  (null)  4       N
3           (null)  (null)  (null)  5       E
3           (null)  (null)  (null)  6       N
4           a       b       c       7       E
4           a1      b1      c1      8       N
5           a       a       c       9       E 
5           a       a       c       10      N

样本数据：

http://sqlfiddle.com/#!18/226bc/5

要求：

情况1：因此，对于表中的排名1，如果flg值 E 的a，c，d为空如果表中列1的值为 N 并且不为空，则列的排名为flg，则loc_rank应该相同。

情况2：因此，对于表中的排名2，如果flg值 E 的a，c，d不为null 列和表中排名2的列，如果flg的值 N 并且具有空值，则应该将loc_rank更改为下一个递增的值。

情况3：因此，对于表中的排名3，如果flg值 E 的a，c，d为空列和表中排名3的列，如果flg的值 N 并且具有空值，则loc_rank应该相同。

情况4：因此，对于表中的排名4，如果flg值 E 的a，c，d不为null 如果表4的值 N 且不为空，但是如果a，b，c在两种情况下相同，则loc_rank应该相同，否则下一个递增值。

我想像这样重新排列输出

flg

Answer 1

您的问题的解决方案：

;with cte
AS
(
SELECT
T1.LOC_RANK AS LOC_RANK1,
T1.b AS b1,
T1.c AS c1,
T1.d AS d1,
T1.rownum AS rownum1,
T1.flg AS flg1,
T2.LOC_RANK AS LOC_RANK2,
T2.b AS b2,
T2.c AS c2,
T2.d AS d2,
T2.rownum AS rownum2,
T2.flg AS flg2,  
CASE WHEN (T1.b IS NOT NULL AND T1.c IS NOT NULL AND T1.d IS NOT NULL)
      AND ( 
                (T2.b IS NULL AND T2.c IS NULL AND T2.d IS NULL)
                 OR
                 (T2.b IS NOT NULL AND T2.c IS NOT NULL AND T2.d IS NOT NULL
                  AND T1.b <> T2.b AND T1.c <> T2.c AND T1.d <> T2.d)
           )
     THEN 1
     ELSE 0
END AS Change     
FROM Table1 T1
INNER JOIN TABLE1 T2
ON T1.LOC_RANK = T2.LOC_RANK
AND T1.flg <> T2.flg AND T1.flg <> 'N'
)
, cte2 
AS
(
SELECT 
LOC_RANK1,
b1,
c1,
d1,
rownum1,
flg1,
LOC_RANK2,
b2,
c2,
d2,
rownum2,
flg2,  
Change,
sum(Change) OVER(ORDER BY rownum2) AS cum_change
FROM cte
)
, finalcte
AS
(
SELECT
CASE WHEN LOC_RANK1 <> 1
      THEN LOC_RANK1 + lag(cum_change) OVER (ORDER BY rownum1)
      ELSE LOC_RANK1
END AS LOC_Rank,      
b1 AS b,
c1 AS c,
d1 AS d,
rownum1 AS rownum,
flg1 AS flg
FROM 
cte2
UNION ALL
SELECT
CASE WHEN LOC_RANK2 = 1 
      THEN 
      CASE WHEN CHANGE = 1
            THEN LOC_RANK2 + CHANGE
            ELSE LOC_RANK2
      END      
      ELSE
        LOC_RANK2 + cum_change
END AS LOC_RANK,        
b2,
c2,
d2,
rownum2,
flg2
FROM 
cte2
)
SELECT *
FROM finalcte
ORDER BY LOC_Rank, flg

输出：

LOC_Rank       b       c       d      rownum    flg
    1        (null)  (null)  (null)    1         E
    1          a       b       c       2         N
    2          a       b       c       3         E
    3        (null)  (null)  (null)    4         N
    4        (null)  (null)  (null)    5         E
    4        (null)  (null)  (null)    6         N
    5          a       b       c       7         E
    6          a1      b1      c1      8         N
    7          a       a       c       9         E
    7          a       a       c       10        N

演示链接：

http://sqlfiddle.com/#!18/f750b/32

SQL根据某种逻辑重新分配等级

1 个答案: