Question

我需要定义一个函数weird_latin_from_sentence，该函数将获取一个句子字符串并返回该句子的拉丁版本。您可能还需要定义另一个名为weird_latin_word的函数，该函数接受一个单词并将其转换为怪异的拉丁语。转换规则为：

1. If the word starts with a consonant then the weird Latin version is formed by moving the first letter to the end of the word and adding the string "eeoow", eg, turtle -> urtleteeoow
2. If the word starts with a non-consonant character then the weird Latin version is simply the English word followed by "meeoow", eg, egg -> eggmeeoow and 121word -> 121wordmeeoow

对于此任务，以下是辅音：

bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ

其他所有内容，包括数字都是非辅音。到目前为止，我已经能够用一个词做到这一点。这是我的程序：

def weird_latin_from_word(english):
    """Sub"""
    weird_latin = ""
    consonants = "bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ"
    for i in range(len(english)):
            if consonants[i] == english[0][i]:
                    english[i] = english[1:] + "eeoow"
                    weird_latin = weird_latin + english

                    return (english)      
            else:
                    english[i] = english[i] + "meeoow"
                    return (english)

如何为句子字符串写这个？使用“列表理解”代替地图功能

例如：

weird_latin = weird_latin_from_sentence("Toby likes his art")

输出：

obyteeoow ikesleeoow isheeoow artmeeoow
print(weird_latin)

Answer 1

您可以改为使用in运算符来执行辅音检查。然后将句子拆分成单词并映射到单词处理功能：

consonants = "bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ"
def weird_latin_from_word(english):
    if english[0] in consonants:
        return english[1:] + english[0] + 'eeoow'
    return english + 'meeoow'
def weird_latin_from_sentence(sentence):
    return ' '.join(weird_latin_from_word(w) for w in sentence.lower().split())

这样：

print(weird_latin_from_sentence("Toby likes his art"))

输出：

obyteeoow ikesleeoow isheeoow artmeeoow

使用“列表理解”将句子转换为奇怪的拉丁语

1 个答案: