Question

例如：

func createArray(_ oneArray: [Int],_ twoArray: [Int],_ threeArray: [Int],_ one: Int,_ two: Int,_ three: Int) -> (oneArrayNew: [Int], twoArrayNew: [Int], threeArrayNew: [Int]){

    // ...
    // ... *random code*
    // ...
    // ...

    return (oneArrayNew, twoArrayNew, threeArrayNew)

}

如果我想使用第一次调用(oneArrayNew, twoArrayNew, threeArrayNew)的输出作为现在使用相同函数的输入来再次调用此函数，我该怎么做？

Answer 1

您可以将元组分配给变量result，然后访问每个成员：

let result = createArray(...
let result2 = createArray(result.oneArrayNew, result.twoArrayNew, ...

或者您可以将调用结果分配给元组以创建三个新变量：

let (a1, a2, a3) = createArray(...
let result2 = createArray(a1, a2, a3, ...

甚至重用现有变量：

var (a1, a2, a3) = createArray(...
(a1, a2, a3) = createArray(a1, a2, a3, ...

完整示例：

我通过从每个数组中删除前N个项目来实现了创建新数组的功能。

在操场上尝试：

func createArray(_ oneArray: [Int],_ twoArray: [Int],_ threeArray: [Int],_ one: Int,_ two: Int,_ three: Int) -> (oneArrayNew: [Int], twoArrayNew: [Int], threeArrayNew: [Int]){

    let oneArrayNew = Array(oneArray.dropFirst(one))
    let twoArrayNew = Array(twoArray.dropFirst(two))
    let threeArrayNew = Array(threeArray.dropFirst(three))

    return (oneArrayNew, twoArrayNew, threeArrayNew)
}

let result = createArray([1,2,3,4], [5,6,7,8], [9,10,11,12], 1, 2, 3)
print(result.oneArrayNew)    // [2, 3, 4]
print(result.twoArrayNew)    // [7, 8]
print(result.threeArrayNew)  // [12]

var (a1, a2, a3) = createArray([1,2,3,4], [5,6,7,8], [9,10,11,12], 2, 2, 2)
print(a1)  // [3, 4]
print(a2)  // [7, 8]
print(a3)  // [11, 12]

(a1, a2, a3) = createArray(a1, a2, a3, 1, 1, 1)
print(a1)  // [4]
print(a2)  // [8]
print(a3)  // [12]

Answer 2

我相信您在这里谈论的是元组。这是一个例子。

func blah(x: Int, y: Int) -> (a: Int, b: Int) {
    return (x,y)
}

let output = blah(1,1)

print(output.0, output.b) // You can access them using indices or the variable names. If they don't have names, you'll have to use indices.

关于将元组作为输入传递的内容，在Swift 2中已被弃用，后来在Swift 3中被移除了。因此，除了传递参数外，您别无选择

blah(output.a, output.b)

或者您甚至可以使用@vacawama answer中所示的多个变量。

如何在Swift中将具有多个输出的函数的输出分配给不同的变量？

2 个答案: