Question

使用C＃，我正在尝试编写一个XML文件，该文件将包含节点（从SQLite DB读取的数据）的未知数（编译时未知，可以在搜索SQLite DB后弄清楚该数字）。），将其命名为相同的（设置）。设置节点的数量可能为数千。

<Set>
  <Setting Name="Ted" empID="60000004">Ted</Setting>
  <Setting Name="Bill" empID="60000007">Bill</Setting>
  <Setting Name="Steve empID="60000010">Steve</Setting>
  <Setting Name="Sara" empID="60000013">Sara</Setting>
  <Setting Name="Tom" empID="60000016">Tom</Setting>
  <Setting Name="Sam" empID="60000019">Sam</Setting>
  <Setting Name="Alex" empID="60000022">Alex</Setting>
  <Setting Name="Sue" empID="60000025">Sue</Setting>
  <Setting Name="Jill" empID="60000028">Jill</Setting>
  <Setting Name="Mya" empID="60000031">Mya</Setting>
</Set>

这是我正在使用的代码，但失败了：

XDocument doc = new XDocument(new XElement("Set"));

while (reader.Read())
{
    doc.Element("Set").Add(new XElement("Setting", _Name));
    doc.Element("Set").Element("Setting").Add(new XAttribute("empID", _ID));
}

doc.Save(_sOutputFolderName + "Employee_Information.xml");

Answer 1

您试图在每个循环中将XAttribute添加到相同的XElement。应该是这样的：

    XDocument doc = new XDocument(new XElement("Set"));

    for (int i = 0; i < 10; i++)
    {
        var _Name = "n" + i ;
        var _ID = "12" + i;
        var setting = new XElement("Setting", _Name );
        setting.Add(new XAttribute("empID", _ID));
        doc.Element("Set").Add(setting);
    }

    Console.WriteLine(doc.ToString());

Answer 2

尝试一下...

XDocument doc = new XDocument(new XElement("Set"));

while (reader.Read()) {
    var setting = new XElement("Setting", "the name"); 
    setting.Add(new XAttribute("empID", "the id"));
    doc.Root.Add(setting);
}

C＃写入XML文件，其中包含未知数目的同名节点

2 个答案: