我正在做一个测验应用程序,在不同的章节中有很多问题。当然,每一章都是一个数组。
但是,现在,我到达了一个特定的章节,要从所有章节中提取所有问题和答案。因此,基本上它是另一个数组中的一个数组。
public void shuffleChapterRandomTest() {
shuffledPositionChapterRandomTest = new String[chapterRandomTestQuestions.length];
for (int k = 0; k < shuffledPositionChapterRandomTest.length; k++) {
shuffledPositionChapterRandomTest[k] = String.valueOf(k);
}
Collections.shuffle(Arrays.asList(shuffledPositionChapterRandomTest));
Log.i("TAG", "shuffle: " + shuffledPositionChapterRandomTest[0] + " " + shuffledPositionChapterRandomTest[1]);
}
public static String shuffledPositionChapterRandomTest[];
private String chapterRandomTestQuestions[][] = {
//This are all the chapters being called
Questions,
chapterTwoQuestions,
chapterThreeQuestions,
chapterFourQuestions,
chapterFiveQuestions,
chapterSixQuestions,
chapterSevenQuestions,
chapterEightQuestions,
chapterNineQuestions,
chapterTenQuestions,
chapterElevenQuestions,
chapterTwelveQuestions,
chapter13Questions,
chapter14Questions
};
//This is my get method
public String[] getChapterRandomTestQuestion(String a) {
return chapterRandomTestQuestions[Integer.parseInt(a)];
}
当我尝试从“问题”中提取字符串作为TextView的setText时。
private void updateQuestion() {
if (questionnumber < questionBank.getChapterRandomTestLength()) {
storeUserData.setInt(Constants.TOTAL_QUESTION,questionBank.getChapterRandomTestLength());
binding.tvCountQuestion.setText(questionnumber+1+"/"+questionBank.getChapterRandomTestLength());
binding.tvQuestion.setText(questionBank.getChapterRandomTestQuestion(shuffledPositionChapterRandomTest[questionnumber]));
binding.tvAnsOne.setText(questionBank.getChapterRandomTestChoice(shuffledPositionChapterRandomTest[questionnumber], 1));
binding.tvAnsTwo.setText(questionBank.getChapterRandomTestChoice(shuffledPositionChapterRandomTest[questionnumber], 2));
binding.tvAnsTnree.setText(questionBank.getChapterRandomTestChoice(shuffledPositionChapterRandomTest[questionnumber], 3));
answer = questionBank.getChapterRandomTestCorrectAnswer(shuffledPositionChapterRandomTest[questionnumber]);
questionnumber++;
显示错误:
必需:Java.lang.String 找到:Java.lang.String []
如何将问题和答案作为字符串而不是数组拉出。谢谢!
答案 0 :(得分:0)
致电时
df.columns.foldLeft( df )( (accDF, c) =>
accDF.withColumn(c, TrimText(col(c)))
)
您正在检索一个questionBank.getChapterRandomTestQuestion(shuffledPositionChapterRandomTest[questionnumber])
,代表String[]
中的一项。您需要使用
chapterRandomTestQuestions
另外,我注意到您正在用整数的String表示填充questionBank.getChapterRandomTestQuestion(shuffledPositionChapterRandomTest[questionnumber])[someNumber]
。为什么不将其设置为shuffledPositionChapterRandomTest
,而又不必转换为String然后又返回int?
还有另一个注意事项/问题:我想您可能为数组写了错误的东西。语法是
int[]
不是
SomeObject[] variable