Question

import commands
    f = open("test.txt","r").readlines()    
    for l in f:
            x = l.strip()
            url = ("https://"+x+"/test")
            c = commands.getoutput("curl -I "+url)
            print (c)

执行代码时，代码在此行中花费很长时间[c = commands.getoutput（“ curl -I” + url）]，我想设置一个时间，例如5秒。如果超过5秒，请移至循环9中的下一行）

Answer 1

您也可以使用requests代替curl来处理响应超时： http://docs.python-requests.org/en/master/user/quickstart/#timeouts。像这样：

import requests
from requests.exceptions import Timeout

import commands

f = open("test.txt","r").readlines()    
for l in f:
    x = l.strip()
    url = ("https://"+x+"/test")
    try:
        response = requests.get(url, timeout=5)
    except Timeout:
        # do something
        continue

Python如何在5秒后继续循环

1 个答案: