我一般都不熟悉Python的Hypothesis库和基于属性的测试。我想使用以下语法生成任意嵌套的策略表达式:
((A和B)或C)
我感觉到递归策略是我想要的,但是我很难理解如何使用它。我仅有的代码似乎只生成一个“级别”的表达。这是我所拥有的:
import unittest
from hypothesis import given
from hypothesis.strategies import text, composite, sampled_from, characters, recursive, one_of
def policy_expressions():
return recursive(attributes(), lambda base_strategy: one_of(base_strategy, policy_expression()))
@composite
def policy_expression(draw):
left = draw(attributes())
right = draw(attributes())
gate = draw(gates())
return u' '.join((left, gate, right))
def attributes():
return text(min_size=1, alphabet=characters(whitelist_categories='L', max_codepoint=0x7e))
def gates():
return sampled_from((u'or', u'and'))
class TestPolicyExpressionSpec(unittest.TestCase):
@given(policy_expression=policy_expressions())
def test_policy_expression_spec(self, policy_expression):
print policy_expression
assert policy_expression # not empty
如何使用假设生成任意嵌套的策略表达式?
答案 0 :(得分:2)
我认为这可能会满足您的要求。
import unittest
from hypothesis import given
from hypothesis.strategies import text, composite, sampled_from, characters, recursive, one_of
def policy_expressions():
return one_of(attributes(), policy_expression())
@composite
def policy_expression(draw):
left = draw(policy_expressions())
right = draw(policy_expressions())
gate = draw(gates())
return u' '.join((left, gate, right))
def attributes():
return text(min_size=1, alphabet=characters(whitelist_categories='L', max_codepoint=0x7e))
def gates():
return sampled_from((u'or', u'and'))
class TestPolicyExpressionSpec(unittest.TestCase):
@given(policy_expression=policy_expressions())
def test_policy_expression_spec(self, policy_expression):
print policy_expression
assert policy_expression # not empty
if __name__ == '__main__':
unittest.main()
答案 1 :(得分:1)
我相信正确的方法是,将base_strategy
作为policy_expression
的参数:
def policy_expressions():
return recursive(attributes(), policy_expression)
@composite
def policy_expression(draw, base_strategy):
left = draw(base_strategy)
right = draw(base_strategy)
gate = draw(gates())
return u' '.join((left, gate, right))
不使用recursive
的已接受答案很可能会遇到假设博客中Generating recursive data帖子中描述的问题。