这是可共享的链接link to file
id = 1wzCjl51u131v1KBgpbiKLJs8DPPakhXCFosfYjp7BY0
是manage downloads文档。
file_id = '11wzCjl51u131v1KBgpbiKLJs8DPPakhXCFosfYjp7BY0'
request = drive_service.files().export_media(fileId=file_id,
mimeType='application/pdf')
fh = io.BytesIO()
downloader = MediaIoBaseDownload(fh, request)
done = False
while done is False:
status, done = downloader.next_chunk()
print ("Download %d%%." % int(status.progress() * 100))
我将文件另存为dd.py,使用f5运行并收到此错误
第2行,在 request = drive_service.files()。export_media(fileId = file_id, NameError:名称“ drive_service”未定义
答案 0 :(得分:0)
首先,您不能确定在共享链接中找到的ID实际上是Google驱动器上文件的ID,但并非总是如此。其实我从来都不知道这种情况
drive_service'未定义
第二,您需要创建驱动器服务并进行身份验证,然后才能运行该代码。您应该尝试遵循python quickstart
ObjectProperty<Upload> upload = new SimpleObjectProperty();
ProgressListener progressListener = (ProgressEvent progressEvent) -> {
if (upload.get() == null) {
return;
}
Platform.runLater(() -> {
directory.setProgressIndicator(upload.get().getProgress().getPercentTransferred() / 100.0d);
MainController.directoryList.set(MainController.directoryList.indexOf(directory), directory);
});
if (progressEvent.getEventType() == ProgressEventType.TRANSFER_COMPLETED_EVENT) {
Platform.runLater(() -> {
directory.setProgressIndicator(1.0d);
MainController.directoryList.set(MainController.directoryList.indexOf(directory), directory);
});
} else if (progressEvent.getEventType() == ProgressEventType.TRANSFER_FAILED_EVENT) {
try {
AmazonClientException ex = upload.get().waitForException();
Platform.runLater(() -> {
Alert alert = new Alert(Alert.AlertType.ERROR);
alert.setTitle("Error Uploading File");
alert.setContentText("Unable to upload file to Amazon S3:" + ex.getMessage());
alert.showAndWait();
});
} catch (InterruptedException e) {
Thread.currentThread().interrupt();
}
}
};
//</editor-fold>
upload.set(s3Service.uploadFile(file, file.length(), file.getName(), progressListener));