前6位的SQL计数值

时间:2018-09-06 13:58:58

标签: mysql

我试图创建一个SQL查询以计算前6个选择中[Over] ='Y'的次数,并且合并查询中出现错误。

查询以获得前6名:

 SELECT TOP 6 [Number]
  ,[Over]
  ,[Goal]
 FROM [Test_Hermes].[dbo].[Test]
 ORDER BY Number desc

查询计数:

SELECT COUNT([Over]) 
FROM [dbo].[Test] 
WHERE [OVER] = 'Y';

合并两个查询:

SELECT COUNT([Over]) 
FROM (SELECT TOP 6 [Number]
  ,[Over]
  ,[Goal]
FROM [Test_Hermes].[dbo].[Test]
ORDER BY Number desc) 
WHERE [OVER] = 'Y';

任何帮助将不胜感激! 谢谢

2 个答案:

答案 0 :(得分:1)

请显示此示例。

 SELECT
   [Number]
  ,[Over]
  ,[Goal]
  , SUM( If(OVER= 'Y',1,0)) AS CNT
 FROM [Test_Hermes].[dbo].[Test]
 ORDER BY Number desc
LIMIT 1,6;

答案 1 :(得分:0)

您不能在子查询中使用订单。

SELECT COUNT([t1].[Over]) 
FROM (SELECT TOP 6 [Number]
    ,[Over] 
    ,[Goal]
  FROM [Test_Hermes].[dbo].[Test]) as t1
WHERE [OVER] = 'Y' ;

如果您需要确定前6名的订单,请使用ROW_NUMBER()

SELECT COUNT([t1].[Over]) 
FROM (SELECT ROW_NUMBER() OVER(PARTITION BY [Number] ORDER BY [Number] DESC) as 'Rank'
    ,[Number]
    ,[Over] 
    ,[Goal]
  FROM [Test_Hermes].[dbo].[Test]) as t1 

WHERE [t1].[OVER] = 'Y' AND [t1].[Rank] <= 6;