分割图的峰到峰以获得1个周期的python

Question

    `android:gravity="end" and  android:gravity="right"` for SDK < 17 and 
     android:gravity="end" for SDK >=17.

所以我想要得到的是让代码使用txt文件中的数据并绘制图形。我坚持的是我无法弄清楚如何进行峰检测以使图显示峰，因为我需要计算从1个峰到另一个峰的值。

import matplotlib.pyplot as plt
import numpy as np
import pdb

file = open("Data1r2.txt", 'r')
lines = file.readlines()
file.close()

设置跟踪

t = []
z = []
y = []
x = []

for line in lines:

  parts = line.split(", ")
  if len(parts) > 3:
column1 = parts[3].split(':')
column2 = column1[1]

column3 = parts[2].split(':')
column4 = column3[1]

column5 = parts[1].split(':')
column6 = column5[1]

column7 = parts[0].split(':')
column8 = column7[1]

T = column2[0:len(column2)]
Z = column4[0:len(column4)]
Y = column6[0:len(column6)]
X = column8[0:len(column8)]

绘制图形

T1 = float(T)
t.append(T1)

Z1 = float(Z)
z.append(Z1)

Y1 = float(Y)
y.append(Y1)

X1 = float(X)
x.append(X1)

Sample of data

我想在1个周期内切出峰到峰的图形