我试图在悬停效果上创建一个简单的图像旋转器。它可以在鼠标悬停时正常工作,但是在使用鼠标移出方法时不起作用。
var imgFlip = $("img").data( "flip" );
var imgOriginal = $("img").data( "original" );
var images = imgFlip.split(/,|, |;|; /);
var index = 0;
function rotateImage()
{
$('.img-rotator').fadeOut('fast', function()
{
$(this).attr('src', images[index]);
$(this).fadeIn('fast', function()
{
if (index == images.length-1)
{
index = 0;
}
else
{
index++;
}
});
});
}
$(document).ready(function()
{
$('.img-rotator')
.mouseover(function () {
var refreshIntervalId = setInterval (rotateImage, 1000);
})
.mouseout(function () {
$(this).attr('src', imgOriginal);
})
});
此处是Jsfiddle示例-https://jsfiddle.net/wbz35L68/15/ 谢谢您的任何建议
答案 0 :(得分:3)
您需要清除setInterval
上的mouseout
。我还重新编写了一些代码以清理内容并缓存引用。您还应该为此使用mouseenter
和mouseleave
。
$(document).ready(function(){
// cache selector
var rotator = $('.img-rotator'),
// grab all data
data = rotator.data(),
// ref flip
imgFlip = data.flip,
// ref original
imgOriginal = data.original,
// get image urls
images = imgFlip.split(/,|, |;|; /),
// start index
index = 0,
// ref interval
refreshIntervalId = null;
function rotateImage(){
rotator.fadeOut('fast', function(){
$(this)
.attr('src', images[index])
.fadeIn('fast', function(){
var last = index === images.length - 1;
index = last ? 0 : index + 1;
});
});
}
rotator
.mouseenter(function(){
refreshIntervalId = setInterval(rotateImage, 1000);
})
.mouseleave(function(){
// clear interval and set null
clearInterval(refreshIntervalId) && (refreshIntervalId = null);
$(this).attr('src', imgOriginal);
})
});
.container {
margin-top: 20px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<div class="row">
<div class="col">
<img class="img-rotator" data-flip="http://www.snorkl.tv/dev/loaderMax/images/bird.png, http://www.snorkl.tv/dev/loaderMax/images/whale.png" data-original="http://www.snorkl.tv/dev/loaderMax/images/crab.png" src="http://www.snorkl.tv/dev/loaderMax/images/crab.png" width="320" height="200"/>
</div>
</div>
</div>