我是Java的新手,因此,如果其中任何一个不清楚,我们深表歉意-我也想将控制台上的内容打印到文本文件中-但是我只希望它最后打印到文件中-所以基本上它将在所有程序中运行(这是一个猜谜游戏),然后一旦完成,它将要求用户输入文件名,然后将控制台上的内容打印到该文件。我对PrintWriter和BufferedWriter等有点熟悉,但是我不确定要打印出控制台上存在的结果(例如,问题是system.out.print和数字3、18)时该怎么做。 ,19是用户输入)。任何帮助将不胜感激!
请猜测1到20之间的数字:3
太低,请重试。请猜一个介于1到20之间的数字:18
太低,请重试。请猜一个介于1到20之间的数字:19
完美!
System.out.println("Enter a file name: ");
String fileName = Keyboard.readInput();
File myFile = new File(fileName);
try (PrintWriter pw = new PrintWriter(new FileWriter(fileName))) {
pw.write(??????);
} catch (IOException e) {
System.out.println(e.getMessage());
}
答案 0 :(得分:2)
如果您希望创建一个系统来允许您使用System.out
以便在打印到控制台的同时打印到文件,则可以为PrintStream创建包装器,以使其也写入到文件。
可以这样做:
public void setupLogger() {
PrintStream stream=System.out;
try {
File file=new File(System.getProperty("user.dir")+"/log.txt");
file.delete();
file.createNewFile();
System.setOut(new WrapperPrintStream(stream,file));
} catch (IOException e) {
e.printStackTrace();
}
for (int i = 0; i <100 ; i++) {
System.out.println("Log test "+i);
}
}
class WrapperPrintStream extends PrintStream{
private PrintStream defaultOutput;
public WrapperPrintStream(@NotNull PrintStream out, File file) throws FileNotFoundException {
super(new PrintStream(new FileOutputStream(file),true), true);
defaultOutput =out;
}
@Override
public void println(String x) {
super.println(x);
defaultOutput.println(x);
}
@Override
public void println() {
super.println();
defaultOutput.println();
}
//etc for all methods.
}
但是,我建议使用Log4J之类的API,它可以自动为您完成所有操作。
答案 1 :(得分:1)
已添加注释以澄清功能
package com.so.test;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.Scanner;
public class Main {
//Declare StringBuilder as global.
private static StringBuilder systemOut = new StringBuilder();
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
//Instead of writing only to System.out only also write to a StringBuilder
writeLnToStreams("Hello!");
//Attempt to write to File
try {
FileOutputStream outputStream = new FileOutputStream(scanner.nextLine());
outputStream.write(systemOut.toString().getBytes());
} catch (IOException e) {
//Will write only to System.err
e.printStackTrace();
}
}
/**
*
* @param output the output to write to System.out and the global StringBuilder
*/
private static void writeToStreams(String output) {
System.out.println(output);
systemOut.append(output);
}
/**
*
* @param output the output to write to System.out and the global StringBuilder
*/
private static void writeLnToStreams(String output) {
System.out.println(output);
systemOut.append(output).append("\n");
}
}
答案 2 :(得分:0)
起初,我对这个问题不太了解,但我想我现在已经明白了。我的演示使用了输入和输出方法,类似于GurpusMaximus在他的回答(对他的+1)中显示的方法,但是我使用了不同的方法来获取输入和输出输出。
这是一个示例演示:
BufferedReader inputStream = null;
PrintWriter outputStream = null;
String writeString = "";
public void testMethod() {
File file = new File("text.txt");
try {
inputStream = new BufferedReader(new InputStreamReader(System.in));
outputStream = new PrintWriter(file);
// Example console text
println("Enter some text: ");
String str = read();
println("Entered: "+str);
// Do this when you are done with the console and want to write to the file
outputStream.print(writeString);
inputStream.close();
outputStream.close();
} catch (IOException e) {
e.printStackTrace();
}
}
// Custom print method that also saves what was printed
public void println(String str) {
System.out.println(str);
writeString += str + System.lineSeparator(); // You can use the line separator call
// to format the text on different lines in
// the file, if you want that
}
// Custom read method that gets user input and also saves it
public String read() {
try {
String str = inputStream.readLine();
writeString += str + System.lineSeparator();
return str;
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
让我知道这是否与您要寻找的东西更相关。