Question

列表是

{id: 11, type: "sell", quantity: 11, price: 155}
{id: 11, type: "sell", quantity: 11, price: 155}
{id: 11, type: "sell", quantity: 11, price: 155}
{id: 12, type: "buy", quantity: 3, price: 189}
{id: 13, type: "buy", quantity: 4, price: 189}
{id: 14, type: "buy", quantity: 2, price: 189}
{id: 14, type: "buy", quantity: 2, price: 189}

（近1000个项目）我想从javascript中的列表中删除重复项，例如，ID为11和14的项具有重复项，因此新列表将在删除后

  {id: 12, type: "buy", quantity: 3, price: 189}
    {id: 13, type: "buy", quantity: 4, price: 189}

重复项将在新数组中被完全删除，而不是它仍然会在新数组中存在

Answer 1

您可以使用Set作为已访问过的id的闭包，并从结果集中删除该对象（如果存在）。

此方法对数据使用单个循环，对每个发现的重复项都进行过滤。

var array = [{ id: 11, type: "sell", quantity: 11, price: 155 }, { id: 11, type: "sell", quantity: 11, price: 155 }, { id: 11, type: "sell", quantity: 11, price: 155 }, { id: 12, type: "buy", quantity: 3, price: 189 }, { id: 13, type: "buy", quantity: 4, price: 189 }, { id: 14, type: "buy", quantity: 2, price: 189 }, { id: 14, type: "buy", quantity: 2, price: 189 }],
    single = array.reduce((s => (r, o) => {
        if (s.has(o.id)) {
            return r.filter(({ id }) => id !== o.id);
        }
        s.add(o.id);
        r.push(o);
        return r;
    })(new Set), []);

console.log(single);

.as-console-wrapper { max-height: 100% !important; top: 0; }

如何从JavaScript中的列表中删除重复项

1 个答案: