`prinBalAgencyComm.sendKeys(testData.get(“ agencyCommissionPB”));
prinBalClientRem.sendKeys(Keys.TAB);
prinBalFrom2.sendKeys(testData.get(“ fromFB2”)); //未找到定位符
prinBalAgencyCommLast.sendKeys(testData.get(“ agencyCommissionLastPB”)); //如何执行此行而不会失败`
答案 0 :(得分:1)
您可以通过使用try catch最终解决此问题。
try{
//code that can result in an exception
prinBalAgencyComm.sendKeys(testData.get("agencyCommissionPB"));
prinBalClientRem.sendKeys(Keys.TAB);
prinBalFrom2.sendKeys(testData.get("fromFB2"));
}catch(Exception e)
{
//actions you want to take in case your locator isnt found or another exception occurs
System.out.println("Exception occured" + e.getMessage());
}finally
{ //the line to be executed without fail
prinBalAgencyCommLast.sendKeys(testData.get("agencyCommissionLastPB"));
}
答案 1 :(得分:0)
您将必须实现try / catch块
try {
element action
} catch (Exception e) {
//whatever you want to happen when it fails
}`
但是我会问自己为什么测试与每次运行不一致?为什么每次都不应该跳过此步骤?
答案 2 :(得分:-1)
您可以使用的一种模式是:
try {}
catch {}
将有问题的代码放在try
块中,并将任何错误代码放在catch
块中。
如果try
中引发异常,则将调用catch
块,而不是继续进行try
中的下一行