我只需要一种从特定URL检索json数据的方法。 我写了这个程序:
'use strict';
var http = require('http');
var request = require("request");
var url = "https://restcountries.eu/rest/v2/name/united"
var server = http.createServer(function (req, res) {
res.writeHead(200, {'Content-Type': 'text/plain'});
request({
url: url,
json: true
}, function (error, response, body) {
if (!error && response.statusCode === 200) {
res.write(JSON.parse(body)) // Print the json response
}else{
res.write("error");
res.end();
}
})
})
server.listen(1338, '127.0.0.1');
console.log('Server running at http://127.0.0.1:1338/');
但是我得到了这个错误:
# node mytest.js
Server running at http://127.0.0.1:1338/
undefined:1
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
^
SyntaxError: Unexpected token o in JSON at position 1
at JSON.parse (<anonymous>)
at Request._callback (/home/xxx/Nodejs/Esempi/emilianotest2.js:18:25)
at Request.self.callback (/home/xxx/Nodejs/Esempi/node_modules/request/request.js:185:22)
at Request.emit (events.js:160:13)
at Request.<anonymous> (/home/xxx/Nodejs/Esempi/node_modules/request/request.js:1161:10)
at Request.emit (events.js:160:13)
at IncomingMessage.<anonymous> (/home/xxx/Nodejs/Esempi/node_modules/request/request.js:1083:12)
at Object.onceWrapper (events.js:255:19)
at IncomingMessage.emit (events.js:165:20)
at endReadableNT (_stream_readable.js:1101:12)
为什么?
编辑:
这是我删除JSON.parse时遇到的错误:
Server running at http://127.0.0.1:1338/
_http_outgoing.js:651
throw new errors.TypeError('ERR_INVALID_ARG_TYPE', 'first argument',
^
TypeError [ERR_INVALID_ARG_TYPE]: The first argument must be one of type string or Buffer
at write_ (_http_outgoing.js:651:11)
at ServerResponse.write (_http_outgoing.js:626:10)
答案 0 :(得分:2)
因为您提供了参数json: true
,所以request
已经为您解析了。然后,当您将非JSON-more-more数组传递给JSON.parse
时,它会在解析之前变成字符串。数组中的对象会获得熟悉的[object Object]
表示形式,并且JSON.parse
会令人窒息,因为[object Object]
看起来不像是正确的数组。
try {
let json = JSON.stringify([{a:1}])
console.log("parsed once:");
console.log(JSON.parse(json));
console.log("parsed twice:");
console.log(JSON.parse(JSON.parse(json)));
} catch(e) {
console.error(e.message);
}
编辑:删除JSON.parse
时,最终会尝试res.write
一个对象。 res.write
不喜欢这样(正如Roland Starke在评论中已经注意到的那样);它更喜欢一个字符串:
res.write(JSON.stringify(body))