Question

这是我的控制人

public function listCurenrTask()
{   
$id = $this->uri->segment(3);
$this->load->model('User_model');
$data['project'] = $this->User_model->select($id);
$this->load->view('taskView',$data );
if ($this->input->post() && $this->input->is_ajax_request()) {                                      $projectid= $this->input->post('$this->session->userdata("projectid")');
$taskstatus = $this->input->post('taskstatus');
$date = $this->input->post('date');
print_r($taskstatus);die();
$credentials = array('projectid'=> $projectid, 'taskstatus'=>$taskstatus, 'date'=>$date);

$this->load->model('User_model');
if(!$this->User_model->taskNotes($credentials)){
    $data['result'] = "fail";
    echo json_encode($data);
} else {
    $data['result'] = "Success";
    echo json_encode($data);
    redirect('/dashboard');
}
} else {
        // $this->load->view('taskview');
    // }
}
}

**在POST方法中搜索了很多教程，并且在这里也看到了回答的问题，但是我的POST仍然不起作用...我想如果你们看到我不喜欢的东西，我应该在这里发布！* *

脚本

<script>
$(document).ready(function(){
    $('#submit').click(function(event){
        event.preventDefault();
        taskstatus=$('#taskstatus').val();
        date=$('#date').val();

        $.ajax({
            type: "POST",
            url: "<?php echo base_url(); ?>taskView"
            data : {taskstatus:taskstatus,date:date},
            dataType: 'json',
            success : function(response){if(response.result==="fail"){
                        $('.show-message').html("Sorry, failed to change your password");
                    }else{
                        $('.show-message').html("Successfully changes your password");
                    }
            },
            error: function() { 
                            alert("Something went wrong");
            }           
        });
    });``
});

https://i.stack.imgur.com/gJHVQ.png

Answer 1

您定义了JS变量吗？

ci中的ajax无法更新ci中的未知错误

1 个答案: