我是hadoop的新手,我试图在一个简单的输入文件上运行map reduce(请参见示例)。 我试图使用两个for循环从属性列表中制作某种笛卡尔积,但由于某种原因,我得到的结果值始终为空。 我尝试过使用它,最终只有在迭代结果时设置结果Text时,它才起作用(我知道,这对我来说也很奇怪)。 如果您能帮助我理解问题,可能是我做错了,我将不胜感激。
这是我拥有的输入文件。
A 1
B 2
C 1
D 2
C 2
E 1
我想得到以下输出:
1 A-C, A-E, C-E
2 B-C, B-D, C-D
所以我尝试实现以下map reduce类: 公共类DigitToPairOfLetters {
public static class TokenizerMapper
extends Mapper<Object, Text, Text, Text> {
private Text digit = new Text();
private Text letter = new Text();
public void map(Object key, Text value, Context context
) throws IOException, InterruptedException {
StringTokenizer itr = new StringTokenizer(value.toString());
while (itr.hasMoreTokens()) {
letter.set(itr.nextToken());
digit.set(itr.nextToken());
context.write(digit, letter);
}
}
}
public static class DigitToLetterReducer
extends Reducer<Text, Text, Text, Text> {
private Text result = new Text();
public void reduce(Text key, Iterable<Text> values,
Context context
) throws IOException, InterruptedException {
List<String> valuesList = new ArrayList<>();
for (Text value :values) {
valuesList.add(value.toString());
}
StringBuilder builder = new StringBuilder();
for (int i=0; i<valuesList.size(); i++) {
for (int j=i+1; j<valuesList.size(); j++) {
builder.append(valuesList.get(i)).append("
").append(valuesList.get(j)).append(",");
}
}
context.write(key, result);
}
}
public static void main(String[] args) throws Exception {
Configuration conf = new Configuration();
Job job = Job.getInstance(conf, "digit to letter");
job.setJarByClass(DigitToPairOfLetters.class);
job.setMapperClass(TokenizerMapper.class);
job.setCombinerClass(DigitToLetterReducer.class);
job.setReducerClass(DigitToLetterReducer.class);
job.setOutputKeyClass(Text.class);
job.setOutputValueClass(Text.class);
FileInputFormat.addInputPath(job, new Path(args[0]));
FileOutputFormat.setOutputPath(job, new Path(args[1]));
System.exit(job.waitForCompletion(true) ? 0 : 1);
}
}
但是此代码将为我提供以下空列表输出:
1
2
当我在for循环中添加set for result时,它似乎可以工作: 公共类DigitToPairOfLetters {
public static class TokenizerMapper
extends Mapper<Object, Text, Text, Text> {
private Text digit = new Text();
private Text letter = new Text();
public void map(Object key, Text value, Context context
) throws IOException, InterruptedException {
StringTokenizer itr = new StringTokenizer(value.toString());
while (itr.hasMoreTokens()) {
letter.set(itr.nextToken());
digit.set(itr.nextToken());
context.write(digit, letter);
}
}
}
public static class DigitToLetterReducer
extends Reducer<Text, Text, Text, Text> {
private Text result = new Text();
public void reduce(Text key, Iterable<Text> values,
Context context
) throws IOException, InterruptedException {
List<String> valuesList = new ArrayList<>();
for (Text value :values) {
valuesList.add(value.toString());
// TODO: We set the valuesList in the result since otherwise the
hadoop process will ignore the values
// in it.
result.set(valuesList.toString());
}
StringBuilder builder = new StringBuilder();
for (int i=0; i<valuesList.size(); i++) {
for (int j=i+1; j<valuesList.size(); j++) {
builder.append(valuesList.get(i)).append("
").append(valuesList.get(j)).append(",");
// TODO: We set the builder every iteration in the loop since otherwise the hadoop process will
// ignore the values
result.set(builder.toString());
}
}
context.write(key, result);
}
}
public static void main(String[] args) throws Exception {
Configuration conf = new Configuration();
Job job = Job.getInstance(conf, "digit to letter");
job.setJarByClass(DigitToPairOfLetters.class);
job.setMapperClass(TokenizerMapper.class);
job.setCombinerClass(DigitToLetterReducer.class);
job.setReducerClass(DigitToLetterReducer.class);
job.setOutputKeyClass(Text.class);
job.setOutputValueClass(Text.class);
FileInputFormat.addInputPath(job, new Path(args[0]));
FileOutputFormat.setOutputPath(job, new Path(args[1]));
System.exit(job.waitForCompletion(true) ? 0 : 1);
}
}
这将给我以下结果:
1 [A C,A E,C E]
2 [B C,B D,C D]
感谢您的帮助
答案 0 :(得分:0)
您的第一种方法似乎很好,您只需添加以下行:
result.set(builder.toString());
之前
context.write(key, result);
就像您在第二个功能中所做的一样。
Context.write刷新输出,由于result只是一个空对象,因此不会传递任何值作为值,只会传递键。因此,在传递之前,您需要在结果中设置值(A-E等)。