我是Android Studio编程的新手。
我已使用php
,ms
sql
将应用程序连接到数据库。
我的php代码:
if( !$conn )
{
echo "Connection could not be established.";
die( print_r( sqlsrv_errors(), true));
}
else{
$user_name = $_POST["username"];
$pass_word = $_POST["password"];
$sql = "select emp_role,emp_id from employee where emp_loginid =(?) and
emp_password =(?)";
$params = array($user_name,$pass_word);
$options = array( "Scrollable" => SQLSRV_CURSOR_KEYSET );
$stmt = sqlsrv_query( $conn, $sql , $params, $options );
$row_count = sqlsrv_num_rows( $stmt );
if ($row_count > 0)
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ){
echo $row["emp_role"];
echo $row["emp_id"];
}
else
echo "username or password is incorrect";
}
这是我的背景代码
public class BackgroundWorker extends AsyncTask<String,Void,String> {
Context context;
AlertDialog alertDialog;
String username, password;
BackgroundWorker(Context ctx) {
context = ctx;
}
@Override
protected String doInBackground(String... params) {
String type = params[0];
String login_url = "http://localhost:8080/sqlsrv.php";
if (type.equals("login")) {
try {
username = (String) params[1];
password = (String) params[2];
URL url = new URL( login_url );
HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection();
httpURLConnection.setRequestMethod( "POST" );
httpURLConnection.setDoOutput( true );
httpURLConnection.setDoInput( true );
OutputStream outputStream = httpURLConnection.getOutputStream();
BufferedWriter bufferedWriter = new BufferedWriter( new OutputStreamWriter( outputStream, "UTF-8" ) );
String post_data = URLEncoder.encode( "username", "UTF-8" ) + "=" + URLEncoder.encode( username, "UTF-8" ) + "&"
+ URLEncoder.encode( "password", "UTF-8" ) + "=" + URLEncoder.encode( password, "UTF-8" );
bufferedWriter.write( post_data );
bufferedWriter.flush();
bufferedWriter.close();
outputStream.close();
InputStream inputStream = httpURLConnection.getInputStream();
BufferedReader bufferedReader = new BufferedReader( new InputStreamReader( inputStream, "iso-8859-1" ) );
String result = "";
String line = "";
while ((line = bufferedReader.readLine()) != null) {
result += line;
}
bufferedReader.close();
inputStream.close();
httpURLConnection.disconnect();
return result;
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
return null;
}
@Override
protected void onPreExecute() {
alertDialog = new AlertDialog.Builder(context).create();
alertDialog.setTitle("Login Status");
}
@Override
protected void onPostExecute(String result) {
/*if(result != null){
Intent intent=new Intent(context,LoginSucess.class);
context.startActivity(intent);
}else{
alertDialog.setMessage(result);
alertDialog.show();
}*/
if(result.equals("username or password is incorrect")) {
Toast.makeText( context, result, Toast.LENGTH_LONG ).show();
}
if(result.equals("AD")){
Intent admin=new Intent(context,Admin.class);
context.startActivity(admin);
}
if(result.equals("EN")){
Intent engineer=new Intent(context,Engineer.class);
context.startActivity(engineer);
}
if(result.equals("SC")){
Intent service=new Intent(context,Service.class);
context.startActivity(service);
}
if(result.equals("SLP")){
Intent Sperson=new Intent(context,SalesPerson.class);
context.startActivity(Sperson);
}
if(result.equals("SLSC")){
Intent Sservice=new Intent(context,SalesService.class);
context.startActivity(Sservice);
}
if(result.equals("SLSU")){
Intent SalesSuper=new Intent(context,SalesSupervisior.class);
context.startActivity(SalesSuper);
}
if(result.equals("SU")){
Intent Supervisior=new Intent(context,Supervisior.class);
context.startActivity(Supervisior);
}
}
}
现在我想使用$ row [“ emp_role”]进行比较,我已经在这样做了 但经过比较我想通过 但是现在我想在下一个意图中传递$ row [“ emp_id”]。
if(result.equals("AD")){
Intent admin=new Intent(context,Admin.class);
context.startActivity(admin);
感谢所有回答我的查询的人。
答案 0 :(得分:0)
在背景工作者中,您有以下内容:
if(result.equals("AD")){
Intent admin=new Intent(context,Admin.class);
admin.putExtra("username", username);
context.startActivity(admin);
然后在您的Admin活动中,您需要在onCreate()方法中执行此操作:
String userName;
if(getIntent().getExtras() != null){
userName = (String) getIntent().getExtras().get("username");
}
希望对您有帮助。
答案 1 :(得分:0)
在您的php代码中,您可以编写:
if ( $row["emp_role"] == "ADMIN")
echo $row["emp_id"] + "-ADMIN";
else
echo $row["emp_id"];
在您的android代码中,您可以编写:
if(result.endsWith("-ADMIN")){
Intent admin=new Intent(context,Admin.class);
context.startActivity(admin);
}
else if(result.equals("AD")){
Intent notAdmin=new Intent(context,NotAdmin.class);
context.startActivity(notAdmin);
}