Question

我正在尝试找出如何使用XmlSerializer从一组类中琐碎地使用一些前缀的Xml。我还希望能够读取相同的Xml（相当简单，但由于使用了更复杂的属性而似乎不见了。

具体用例是电子书中的opf文件。

这是我要生成的Xml的示例

<?xml version='1.0' encoding='utf-8'?>
<package xmlns="http://www.idpf.org/2007/opf" version="2.0" unique-identifier="uuid_id">
  <metadata xmlns:xsi=""dchttp://www.w3.org/2001/XMLSchema-instance" xmlns:opf="http://www.idpf.org/2007/opf" xmlns:dcterms="http://purl.org/dc/terms/" xmlns:calibre="http://calibre.kovidgoyal.net/2009/metadata" xmlns:dc="http://purl.org/dc/elements/1.1/">
    <dc:publisher>Baen Publishing Enterprises</dc:publisher>
    <meta name = "calibre:series_index" content="1"/>
    <dc:rights>2002 by Lois McMaster Bujold.</dc:rights>
    <dc:language>en-us</dc:language>
    <dc:creator opf:file-as="Bujold., Lois McMaster " opf:role= "aut" > Lois McMaster Bujold.</dc:creator>
    <meta name = "calibre:timestamp" content= "2010-05-07T17:42:06.859000+00:00" />
    <dc:title>Miles Errant</dc:title>
    <meta name = "cover" content= "RW_0743435583_Cover" />
    <dc:date>2002-09-01T04:00:00+00:00</dc:date>
    <dc:contributor opf:role= "bkp" > calibre(0.6.51)[http://calibre.kovidgoyal.net]</dc:contributor>
    <dc:identifier opf:scheme = "ISBN" > 0 - 7434 - 3558 - 3 </dc:identifier >
    <dc:identifier id = "uuid_id" opf:scheme = "uuid" > c7e276b6 - 1a12 - 4130 - a7ac - b2febb9730fb </dc:identifier >
    <dc:subject > Science Fiction </dc:subject >
  </metadata > 
</package>

对应的类如下：-

public class package
{
    public metadata metadata { get; set; }
}

public class metadata
{
    [XmlElement(Namespace = "http://purl.org/dc/elements/1.1/", Form = System.Xml.Schema.XmlSchemaForm.Qualified)]
    public string title { get; set; }
    [XmlElement(Namespace = "http://purl.org/dc/elements/1.1/", Form = System.Xml.Schema.XmlSchemaForm.Qualified)]
    public string language { get; set; }
    [XmlElement(Namespace = "http://purl.org/dc/elements/1.1/", Form = System.Xml.Schema.XmlSchemaForm.Qualified)]
    public string creator { get; set; }
    [XmlElement(Namespace = "http://purl.org/dc/elements/1.1/", Form = System.Xml.Schema.XmlSchemaForm.Qualified)]
    public string publisher { get; set; }
    [XmlElement(Namespace = "http://purl.org/dc/elements/1.1/", Form = System.Xml.Schema.XmlSchemaForm.Qualified)]
    public string rights { get; set; }
    [XmlElement(Namespace = "http://purl.org/dc/elements/1.1/", Form = System.Xml.Schema.XmlSchemaForm.Qualified)]
    public List<identifier> identifier { get; set; }
}

public class identifier
{
    [XmlAttribute(Namespace = "http://purl.org/dc/elements/1.1/")]
    public string id { get; set; }
    [XmlAttribute(Namespace = "http://www.idpf.org/2007/opf")]
    public string scheme { get; set; }
    [XmlText]
    public string Identifier { get; set; }
}

而编写代码（当前）是

    public static Stream WriteToStream(package p)
    {
        XmlSerializerNamespaces namespaces = new XmlSerializerNamespaces();
        namespaces.Add("dc", "http://purl.org/dc/elements/1.1/");
        namespaces.Add("", "http://www.idpf.org/2007/opf");
        XmlSerializer serialiser = new XmlSerializer(typeof(package));


        Stream s = new MemoryStream();
        serialiser.Serialize(s, p, namespaces);
        s.Position = 0;
        return s;
    }

这将产生以下结果。

<?xml version="1.0"?>
<package>
  <metadata>
    <title xmlns="http://purl.org/dc/elements/1.1/">Miles Errant</title>
    <language xmlns="http://purl.org/dc/elements/1.1/">en-us</language>
    <creator xmlns="http://purl.org/dc/elements/1.1/"> Lois McMaster Bujold.</creator>
    <publisher xmlns="http://purl.org/dc/elements/1.1/">Baen Publishing Enterprises</publisher>
    <rights xmlns="http://purl.org/dc/elements/1.1/">2002 by Lois McMaster Bujold.</rights>
    <identifier d3p1:scheme="ISBN" xmlns:d3p1="http://www.idpf.org/2007/opf" xmlns="http://purl.org/dc/elements/1.1/"> 0 - 7434 - 3558 - 3 </identifier>
    <identifier id="uuid_id" d3p1:scheme="uuid" xmlns:d3p1="http://www.idpf.org/2007/opf" xmlns="http://purl.org/dc/elements/1.1/"> c7e276b6 - 1a12 - 4130 - a7ac - b2febb9730fb </identifier>
    </metadata>
  <manifest />
</package>

如果我将dc名称空间添加到根元素中，则会得到dc前缀，但是我可以再反序列化该示例。

如果这要比XmlSerializer要处理的复杂得多，那么我可以手动编写文件，但我宁愿通过标记而不是代码来完成。

长篇致歉。

非常感谢。

伊恩

Answer 1

看起来就像这里的混乱只是前两个元素上的名称空间；在本地，我有：

[XmlRoot("package", Namespace = "http://www.idpf.org/2007/opf")]
public class Package
{
    [XmlElement("metadata", Namespace = "http://www.idpf.org/2007/opf")]
    public PackageMetadata Metadata { get; set; }
}

现在可以正确地序列化和反序列化了。

XmlSerializer和复杂前缀

1 个答案: