使用昂首阔步的csv文件并从中读取内容

时间:2018-09-05 06:38:36

标签: java swagger

#Defines the sections
tags:    
   - name: CasCsvFile
     description: Obtain Csv file form CAS and parse it.
     externalDocs:
      description: Find out more
      url: ''
schemes:
  - https
paths:
  '/CasCsvFile':
    post:
      tags:
        - CasCsvFile
      summary: Find csv file
      description: Returns csv file
      operationId: getCSV
     # produces:
       # - application/json
      consumes:
       - multipart/form-data #and/or application/x-www-form-urlencoded
      parameters:
        - name: fileUpload
          in: formData
          description: The uploaded file data
          required: true
          type: file
      responses:
        '200':
          description: successful operation
          #schema:
           #$ref: '#/definitions/NounInfo'
        '400':
          description: Invalid ID supplied
        '404':
          description: Noun not found
   scopes:
  api_key:
    type: apiKey
    name: api_key
    in: header
externalDocs:
  description: Find out more about Swagger

这是我为挥霍而编写的代码。 当我将文件上传到编辑器中时,提示文件未找到。

我想从招摇中读取一个csv文件并将其存储在数据库中

0 个答案:

没有答案