Question

所以我试图用Python创建一个密码系统，由此，在经过一定数量的不正确尝试之后，用户将被阻止访问例如5分钟。我目前不确定重新运行相同文件然后以这种方式使用后如何保留变量的值。因为我现在还不熟悉Python，所以有人可以帮我吗？

更新：

在尝试了一段时间的代码之后，乔纳斯·沃尔夫（Jonas Wolff）为我提供了我最终确定以下代码的代码：

def password(): 
    count = 0 
    currentTime = float(time.time()) 
    passwordList = ["something", "password", "qwerty", "m42?Cd", "no"] 
    passwordNum = random.randint(0, 4) 
    password = passwordList[passwordNum] 
    with open("password.txt", "r") as file:
        check = file.readline()
        initialTime = file.readline()
        if initialTime=="":
            initialTime==0
    if int(check)==1 and (currentTime-float(initialTime))<300:
        print("You are still locked")
        print("Please try again in", int(300-(currentTime-float(initialTime))), "seconds.")
        quit()
    print("The randomised password is No.", passwordNum+1) #Prints a string to let the user know which password was randomly selected
    while count<5:
        inp = input("Enter the Password: ")
        if inp==password:
            print("Access Granted")
            print()
            f = open("password.txt", "w")
            f.write("0\n0")
            f.close()
            select()
        elif (count+1)==5:
            print("You have been locked")
            print("Please try again in 5 minutes")
            f = open("password.txt", "w")
            f.write("1\n")
            f.write(str(currentTime))
            f.close()
            quit()
        else:
            count+=1
            print("Incorrect Password")
            print("You have", 5-count, "tries left.")
            continue

非常感谢您提供的帮助以及耐心回答我的问题。

Answer 1

import YourProgram # this is the program you want to run, if the program runs automaticly when opened then move the import to the part where i wrote YourProgram() and delete the YourPregram() line
import time

pswd = "something"

count = 0

with open("PhysxInit.txt","r") as file:
    file_info = file.readline()
    numa = file_info.count("1")
    count = numa


while True:
    with open("PhysxInit.txt","r") as file:
        file_info = file.readline()
        tima = file.readline()


    inp = input("What is the password:")



    if inp == pswd:

        if tima == "":
            tima = "0"  # this should solve yoúr problem with float convertion however it doesn't make sence that this step should be needed


        if str(file_info[:5]) != "11111" or time.time() > float(tima):
            YourProgram() # this is just meant as the thing you want to do when when granted acces i magined you where blocking acces to a program.
            f = open("PhysxInit.txt", "w")
            f.write("\n")
            f.close()
            break
    else:
        count += 1
        f = open("PhysxInit.txt", "w")
        f.write(("1"*count)+"\n"+str(tima))
        if count == 5:
             f.write(str(time.time()+60*5))
        f.close()

#f = open("PhysxInit.txt", "w")
#f.write("\n")
#f.close()

这项工作吗？只要确保您有一个名为PhysxInit.txt的文本文件

运行该程序后，几次猜错了我的txt文件，就像这样。

11111
1536328469.9134998

虽然数字可能有所不同，但看起来应该像我的。

要按照您的要求阅读特定行，您需要执行以下操作：

with open("PhysxInit.txt", "r") as f:
    for w,i in enumerate(f):
        if w == #the number line you want:
            # i is now the the line you want, this saves memory space if you open a big file

经过一定次数的尝试后，Python密码系统已锁定

1 个答案: