我使用GooglePlacesAPI和jQuery输出基于Google Place ID的企业的Google评论。两个变量不再输出数据。
author_name
不再输出用户名,所有评论显示用户名均来自“ A Google User”
profile_photo_url
不再输出用户照片,它返回空白。
author_name
和profile_photo_url
都记录在Google地方详情(https://developers.google.com/places/web-service/details)
评论主体和星星仍然正确输出。
还有另一种方法来调用此数据吗?
编辑:此问题是由于Google Places API中的错误已修复。
答案 0 :(得分:1)
这已被Google确认为Google广告客户社区中的错误。请参阅我对相关问题的回复: Google Place API author_name Anonymous Problem
答案 1 :(得分:0)
当有memcpy
时...例如示例中的一个:
https://www.google.com/maps/contrib/106422854611155436041/reviews
然后可以将其转换为ID为//Initial pointer to array..
float bytes2[] = {39, 77, 111, 111, 102, 33, 39, 0};
float* uint8Pointer2 = &bytes[2];
memcpy(uint8Pointer2, &bytes2[0], bytes2.size() * sizeof(float));
//Shallow/Shadowing Pointer...
float* uint8Pointer = uint8Pointer2;
float bytes[] = {391, 771, 1111, 1111, 1012, 331, 319, 10};
memcpy(uint8Pointer, &bytes[0], bytes.size() * sizeof(float));
//Pointer to pointer..
float** uint8Pointer1 = &uint8Pointer;
//Bad.. uint8Pointer1 and &uint8Pointer is the same damn thing (same memory address)..
//See the line above (float** uint8Pointer1 = &uint8Pointer)..
memcpy(uint8Pointer1, &uint8Pointer, 8 * sizeof(uint8Pointer));
//The memcpy is unnecessary because it already pointers to the same location.. plus it's also wrong lol.
的G +个人资料:
https://plus.google.com/106422854611155436041
...,可以通过People API进行解析(需要登录)。