我有一个数据框df1
,其中包含这样的产品列表:
| SKU | Product | Model | Size |
|-----|---------|-------|--------|
| 1 | X | A | Small |
| 2 | X | B | Large |
| 3 | X | B | Medium |
...
还有一个数据框df2
,其中包含每个型号和尺寸的价格,如下所示:
| Model | Small | Medium | Large |
|-------|-------|--------|-------|
| A | 10 | 12 | 15 |
| B | 8 | 9 | 10 |
| C | 7 | 8 | 12 |
| D | 12 | 13 | 14 |
...
我想要的是将df1
中的产品型号和尺寸与df2
中的数据进行匹配,以便我可以在第一个数据框中添加带有价格的新列。
结果应为以下内容:
| SKU | Product | Model | Size | Price |
|-----|---------|-------|--------|-------|
| 1 | X | A | Small | 10 |
| 2 | X | B | Large | 10 |
| 3 | X | B | Medium | 9 |
...
如何使用R做到这一点?
答案 0 :(得分:1)
以下是一种方法。您可以重塑df2
并创建一个名为Price
的新列。然后,您合并数据。
library(dplyr)
library(tidyr)
df1 <- data.frame(SKU = 1:3,
Product = c("X", "X", "X"),
Model = c("A", "B", "B"),
Size = c("Small", "Large", "Medium"),
stringsAsFactors = FALSE)
df2 <- data.frame(Model = LETTERS[1:4],
Small = c(10, 8, 7, 12),
Medium = c(12, 9, 8, 13),
Large = c(15, 10, 12, 14),
stringsAsFactors = FALSE)
gather(df2, key = Size, value = Price, -Model) %>%
left_join(df1, ., by = c("Model", "Size"))
SKU Product Model Size Price
1 1 X A Small 10
2 2 X B Large 10
3 3 X B Medium 9
答案 1 :(得分:1)
这是使用基数R的解决方案:
Jazzurro的数据:
df1 <- data.frame(SKU = 1:3,
Product = c("X", "X", "X"),
Model = c("A", "B", "B"),
Size = c("Small", "Large", "Medium"),
stringsAsFactors = FALSE)
df2 <- data.frame(Model = LETTERS[1:4],
Small = c(10, 8, 7, 12),
Medium = c(12, 9, 8, 13),
Large = c(15, 10, 12, 14),
stringsAsFactors = FALSE)
1个班轮:
df1$Price <- apply(df1, 1, function(x) df2[df2[,"Model"] %in% x["Model"],x["Size"]] )
# SKU Product Model Size Price
#1 1 X A Small 10
#2 2 X B Large 10
#3 3 X B Medium 9