传播语法以删除

Question

我不会删除一把钥匙。看这个

console.log(state);

我得到{1: {here is next object}}， 下一个

const { 1: deletedValue, ...newState } = state;
console.log(newState);
console.log(state);

我得到

{1: {here is next object}}
{1: {here is next object}}

删除不起作用。我不明白为什么

您在评论中邀请您描述数据看起来如何更准确：

state: {1: {id: 1, content: {name: "xyz", surname: "dsd"}},
2: {id: 2, content: {name: "abc", surname: "dsq"}}
}

Answer 1

这似乎是babeljs问题。

将数字作为destructuring assignment的属性的问题。

var object = { 1: 40, foo: 41, bar: 42, baz: 43 },
    { 1: y, foo: z, ...x } = object;
    //^
    
console.log(x);
console.log(y);
console.log(z);

将字符串数字而不是数字作为目标属性。

var object = { 1: 40, foo: 41, bar: 42, baz: 43 },
    { '1': y, foo: z, ...x } = object;
    //^^^
    
console.log(x);
console.log(y);
console.log(z);