我正在尝试将TK文本小部件内的内容复制到文件中。 我的意思是,复制当前文本框中的所有单词和字母,然后将它们复制到文件中,因此,当我进入文件时,我将看到程序上次运行后文本框中的内容。 这是我的代码:(有些可能早先见过)
import datetime
from time import gmtime, strftime
from tkinter import *
root = Tk()
root.geometry("500x800")
text1 = Label(root, text="Menu", font='Verdana, 15')
text1.pack()
coststr = StringVar()
cost = 0
coststr.set(f'£ {cost}')
menu = ["Burger", "Chips", "Milkshake"]
textln = Label(root, text="\n")
textln.pack()
day = datetime.date.today()
def choiceburger():
global cost
global coststr
cost += 1.99
cost = round(cost, 2)
coststr.set(f'£ {cost}')
txt.insert(END, 'Burger £1.99\n',)
def choicechips():
global cost
global coststr
cost += 1.49
cost = round(cost, 2)
coststr.set(f'£ {cost}')
txt.insert(END, 'Chips £1.49\n',)
def choicemilkshake():
global cost
global coststr
cost += 0.99
cost = round(cost, 2)
coststr.set(f'£ {cost}')
txt.insert(END, 'Milkshake £0.99\n',)
def pay():
global cost
global coststr
txt.insert(END, "Total Charges: ")
txt.insert(END, coststr.get())
from tkinter import messagebox
msgbox = messagebox.askokcancel("", "Are You Sure You Want To Buy These Items?")
printrec()
if msgbox == True:
txt.delete('1.0', END)
cost = 0
cost = round(cost, 2)
coststr.set(f'£ {cost}')
txtboxmsg()
else:
quit()
burgerbutton = Button(root, text=" Burger £1.99 ", command=choiceburger)
burgerbutton.pack()
chipsbutton = Button(root, text=" Chips £1.49 ", command=choicechips)
chipsbutton.pack()
milksbutton = Button(root, text=" Milkshake £0.99 ", command=choicemilkshake)
milksbutton.pack()
textln = Label(root, text="\n")
textln.pack()
textln = Label(root, text="\n")
textln.pack()
textln = Label(root, text="\n")
textln.pack()
txt = Text(root)
txt.pack()
def txtboxmsg():
txt.insert(END, strftime("%H:%M:%S "))
txt.insert(END, day)
txt.insert(END, " Jake's Fast Food\n")
txtboxmsg()
def gettxt():
inputt=txt.get("1.0","end-1c")
print(inputt)
def printrec():
f = open(r"F:/fast food code/receipts.txt", "a")
f.write("\n{}\n".format(gettxt()))
f.close()
costlabel = Label(root, textvariable=coststr, font='Verdana, 20')
costlabel.pack()
textln = Label(root, text="\n")
textln.pack()
paybutton = Button(root, text="Pay", command=pay, font='Verdana, 25')
paybutton.pack()
textln = Label(root, text="\n")
textln.pack()
您可以看到我制作了一个程序,其作用类似于商店,并在完成后打印收据。我想将该收据(文本框txt
)打印到文件F:/fast food code/receipts.txt
中。每当我将收据保存到文件中时,我都会进入文件内部进行查看,而我所得到的只是“无”,好像什么都没有保存到文件中一样。
为了更加清楚,我的问题是如何将“文本”小部件的内容直接复制到文件中?
答案 0 :(得分:1)
您没有从函数返回inputt
。试试:
import datetime
from time import gmtime, strftime
from tkinter import *
root = Tk()
root.geometry("500x800")
text1 = Label(root, text="Menu", font='Verdana, 15')
text1.pack()
coststr = StringVar()
cost = 0
coststr.set(f'£ {cost}')
menu = ["Burger", "Chips", "Milkshake"]
textln = Label(root, text="\n")
textln.pack()
day = datetime.date.today()
def choiceburger():
global cost
global coststr
cost += 1.99
cost = round(cost, 2)
coststr.set(f'£ {cost}')
txt.insert(END, 'Burger £1.99\n',)
def choicechips():
global cost
global coststr
cost += 1.49
cost = round(cost, 2)
coststr.set(f'£ {cost}')
txt.insert(END, 'Chips £1.49\n',)
def choicemilkshake():
global cost
global coststr
cost += 0.99
cost = round(cost, 2)
coststr.set(f'£ {cost}')
txt.insert(END, 'Milkshake £0.99\n',)
def pay():
global cost
global coststr
txt.insert(END, "Total Charges: ")
txt.insert(END, coststr.get())
from tkinter import messagebox
msgbox = messagebox.askokcancel("", "Are You Sure You Want To Buy These Items?")
if msgbox == True:
printrec()
txt.delete('1.0', END)
cost = 0
cost = round(cost, 2)
coststr.set(f'£ {cost}')
txtboxmsg()
else:
quit()
burgerbutton = Button(root, text=" Burger £1.99 ", command=choiceburger)
burgerbutton.pack()
chipsbutton = Button(root, text=" Chips £1.49 ", command=choicechips)
chipsbutton.pack()
milksbutton = Button(root, text=" Milkshake £0.99 ", command=choicemilkshake)
milksbutton.pack()
textln = Label(root, text="\n")
textln.pack()
textln = Label(root, text="\n")
textln.pack()
textln = Label(root, text="\n")
textln.pack()
txt = Text(root)
txt.pack()
def txtboxmsg():
txt.insert(END, strftime("%H:%M:%S "))
txt.insert(END, day)
txt.insert(END, " Jake's Fast Food\n")
txtboxmsg()
def gettxt():
inputt=txt.get("1.0",END)
print(inputt)
return inputt
def printrec():
f = open(r"receipts.txt", "a")
f.write("\n{}\n".format(gettxt()))
f.close()
costlabel = Label(root, textvariable=coststr, font='Verdana, 20')
costlabel.pack()
textln = Label(root, text="\n")
textln.pack()
paybutton = Button(root, text="Pay", command=pay, font='Verdana, 25')
paybutton.pack()
textln = Label(root, text="\n")
textln.pack()
答案 1 :(得分:1)
您的问题出在def gettxt():
函数中。
更改此:
def gettxt():
inputt=txt.get("1.0","end-1c")
print(inputt)
对此:
def gettxt():
global txt
inputt=txt.get("1.0","end-1c")
print(inputt)
return inputt
您可以通过执行printrec()
中的工作来绕过此功能。
尝试以下方法:
def printrec():
global txt
f = open(r"./receipts.txt", "a")
f.write("\n{}\n".format(txt.get("1.0","end-1c")))
f.close()
您的代码还有其他一些问题。确保使用正确的缩进。在gettxt()
中,您缩进了8个空格而不是4个空格。您也不需要在标签中使用空格。您可以使用填充来获取所需的内容。
作为参考,我已经将您的代码更新为一个类,并对其进行了一些整理。 这样可以避免对全局变量的需要,并为您提供一些有关需要和不需要变量名的参考,以及如何用填充物来分隔内容而不添加更多标签。
import datetime
from time import strftime
from tkinter import messagebox
# import tkinter as tk helps to prevent an accidental overriding of variable/function names in the namespace.
import tkinter as tk
# Using a class we can get rid of global and manage things much easier using class attributes
class App(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
self.geometry("500x800")
# This weight helps the widgets in column 0 resize with the window.
self.columnconfigure(0, weight=1)
self.coststr = tk.StringVar()
self.cost = 0
self.coststr.set('£ {}'.format(self.cost))
self.menu = ["Burger", "Chips", "Milkshake"]
self.day = datetime.date.today()
#this label is using `pady` to set the padding below the widget so you do not need spacer labels
tk.Label(self, text="Menu", font='Verdana, 15').grid(row=0, column=0, pady=(0, 20))
self.btn_frame = tk.Frame(self)
self.btn_frame.grid(row=1, column=0)
# These buttons are placed in a frame so they can expand to fit the frame and be all the same size.
tk.Button(self.btn_frame, text="Burger: £1.99", command=self.choiceburger).grid(row=0, column=0, sticky="ew")
tk.Button(self.btn_frame, text="Chips: £1.49", command=self.choicechips).grid(row=1, column=0, sticky="ew")
tk.Button(self.btn_frame, text="Milkshake: £0.99", command=self.choicemilkshake).grid(row=2, column=0, pady=(0, 80), sticky="ew")
self.txt = tk.Text(self)
self.txt.grid(row=2, column=0)
tk.Label(self, textvariable=self.coststr, font='Verdana, 20').grid(row=3, column=0, pady=(0, 40))
tk.Button(self, text="Pay", command=self.pay, font='Verdana, 25').grid(row=4, column=0)
self.txtboxmsg()
def choiceburger(self):
self.cost += 1.99
self.cost = round(self.cost, 2)
self.coststr.set('£ {}'.format(self.cost))
self.txt.insert("end", 'Burger £1.99\n',)
def choicechips(self):
self.cost += 1.49
self.cost = round(self.cost, 2)
self.coststr.set('£ {}'.format(self.cost))
self.txt.insert("end", 'Chips £1.49\n',)
def choicemilkshake(self):
self.cost += 0.99
self.cost = round(self.cost, 2)
self.coststr.set('£ {}'.format(self.cost))
self.txt.insert("end", 'Milkshake £0.99\n',)
def pay(self):
self.txt.insert("end", "Total Charges: ")
self.txt.insert("end", self.coststr.get())
msgbox = messagebox.askokcancel("", "Are You Sure You Want To Buy These Items?")
self.printrec()
if msgbox == True:
self.txt.delete('1.0', "end")
self.cost = 0
self.cost = round(self.cost, 2)
self.coststr.set('£ {}'.format(self.cost))
self.txtboxmsg()
else:
self.destroy()
def txtboxmsg(self):
self.txt.insert("end", strftime("%H:%M:%S "))
self.txt.insert("end", self.day)
self.txt.insert("end", " Jake's Fast Food\n")
def printrec(self):
# this with open statement will also close once the write is complete.
with open(r"./receipts.txt", "a") as f:
# this write statement gets the data directly from txt so you do not need the gettxt() function.
f.write("\n{}\n".format(self.txt.get("1.0","end-1c")))
app = App()
app.mainloop()