Question

id  color
1   Yellow
1   Pink
2   Yellow
2   blue
3   Yellow
3   Yellow
4   Red

只希望所有行的颜色都相同的ID。

尝试了多种方法，但没有得到任何答案。

;WITH CTE AS (
select ROW_NUMBER() OVER(PARTITION BY A.ID,A.COLOR ORDER BY A.ID,A.COLOR)RNO,A.ID,A.COLOR from COLOR a join COLOR b on a.id = b.id and a.color=b.color
)
SELECT DISTINCT ID, COLOR FROM CTE --WHERE RNO > 1

SELECT *
FROM color a join (
    SELECT id, color, count(*) as qty
    FROM color
    GROUP BY id, color
    HAVING COUNT(*) > 1
) b on a.id = b.id and a.color = b.color


select * from (
Select color,id,count(1)cnt from COLOR
group by color,id
having count(1) = 1

union all

Select color,id,count(1)cnt from COLOR
group by color,id
having count(1) > 1

) as t  where cnt  between 1 and 4

Answer 1

GROUP BY和HAVING将完成此工作。 COUNT(DISTINCT color)将在每个组中返回不同的颜色，如果返回1，则该组中的所有行都有一种颜色。

select id from my_table
group by id
having count(distinct color) = 1

Answer 2

您可以使用not exists：

select c.*
from color c
where not exists (select 1 from color c1 where c1.id = c.id and c1.color <> c.color);

仅查找所有行上颜色相同的那些ID

2 个答案: