以下是查询:
SELECT product.catalog_product_id AS catalog_id, listing.id AS listing_id,
product.size AS size, 0 AS amount,
listing.list_price AS price,
listing.created_at AS created_date
FROM product
INNER JOIN listing ON listing.product_id = product.id
WHERE product.catalog_product_id = XXXX
AND listing.id = (
SELECT l.id
FROM listing l
INNER JOIN product i ON l.product_id = i.id
WHERE i.size = product.size AND i.catalog_product_id = XXXX
ORDER BY l.list_price ASC, l.created_at ASC
LIMIT 1
)
子查询是获取最低价格的列表ID。子查询因Order by而变慢。我已经创建了索引,仍然需要5到6秒钟。
表结构:
目录:这是主产品目录表
Catalog
-------
id
sku
name
description
products:存储产品型号(尺寸选项)
Products
--------
id
catalog_id
size
列表::存储产品列表,一个“产品尺寸”选项可以包含多个具有不同价格的产品列表。
listing
---------
id
product_id
list_price
created_at
它显示每个列表和大小的最低价格。
答案 0 :(得分:0)
由于子查询实际上没有执行任何操作,请尝试执行此操作。如果这不起作用,请发布explain语句的输出,并避免使用表别名(如“ l”和“ i”)。真的很难阅读,而且出错的机会也大大增加(例如,由于某种原因您自己加入了“ product.size”)。
SELECT
product.catalog_product_id AS catalog_id,
listing.id AS listing_id,
product.size AS size, 0 AS amount,
listing.list_price AS price,
listing.created_at AS created_date
FROM product
INNER JOIN listing
ON listing.product_id = product.id
WHERE product.catalog_product_id = ?
ORDER BY listing.list_price ASC,
listing.created_at ASC
LIMIT 1
答案 1 :(得分:0)
我能够解决这个问题。
SELECT product.catalog_product_id AS catalog_id, listing.id AS listing_id,
product.size AS size,
listing.list_price AS price,
listing.created_at AS created_date
FROM product
INNER JOIN listing ON listing.product_id = product.id
AND product.catalog_product_id = XXXX
AND listing.id IN
(
SELECT MIN(l.id)
FROM listing l
INNER JOIN product i ON l.product_id = i.id
WHERE i.catalog_product_id = XXXX
AND list_price = (
SELECT MIN(list_price)
FROM listing l
INNER JOIN product it ON l.product_id = it.id
WHERE it.catalog_product_id = XXXX AND it.size = i.size
)
GROUP BY i.size
)
代替使用:
ORDER BY l.list_price ASC, l.created_at ASC LIMIT 1
我已经使用最小(价格)和按大小分组以获取最小价格清单。
查询性能从5秒提高到0.5秒
谢谢!