Question

我正在将Perl代码转换为php。
该Perl代码将Heredoc用于多部分/表单数据，我想在php中实现它。
但是，我的php代码无法达到相同的结果（空）。
我的php代码有问题吗？
另外，我应该在php中使用Heredoc与Perl代码做相同的事情吗？
我不知道怎么了。

谢谢您的帮助！

* Perl代码

if($csrf_access_token ne ''){
    my $req2 = HTTP::Request->new(POST => $search_api);
    my $shinaban1 = 'g3717380';
    open(my $out, '>out_search.tab');
    open(my $in, 'g3717380.jpg');
    my $image;
    binmode($in);
    read($in, $image, -s 'g3717380.jpg');
    close($in);

    my $boundary= 'test';
    $req2->content_type('multipart/form-data;boundary='.$boundary);
    $req2->header("Cookie"=>"access_token_cookie=$access_token_cookie; csrf_access_token=$csrf_access_token");

    $req2->content(<<"POST_DATA");  #Heredoc start
--$boundary
Content-Disposition: form-data; name="num_result"
Content-Type: text/plain

$num_result
--$boundary
Content-Disposition: form-data; name="img"; filename="search.jpg"
Content-Type: image/jpeg

$image
--$boundary--
POST_DATA   #Heredoc end

    my $res = $ua->request($req2);
    if($res->is_success) {
        print $out $res->content;
        print $res->content, "\n";
    }
    else {
    print $res->headers_as_string;
        print $res->status_line, "\n";
        print $res->content, "\n";
    }
}

*我的PHP代码

...
$image_data=file_get_contents('g3717380.jpg');
$boundary = "test";
$data =
<<<EOF

--$boundary
Content-Disposition: form-data; name="num_result"
Content-Type: text/plain

$num_result
--$boundary
Content-Disposition: form-data; name="img"; filename="search.jpg"
Content-Type: image/jpeg

$image_data
--$boundary--
EOF;

$ch2 = curl_init($search_url);
curl_setopt($ch2, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch2, CURLOPT_POST, true);
curl_setopt($ch2, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch2, CURLOPT_POSTFIELDS, $data);
curl_setopt($ch2, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch2, CURLOPT_HTTPHEADER, array(
    'Content-Type: multipart/form-data;boundary='.$boundary)
);
$result= curl_exec($ch2);
curl_close($ch2);
?>

如何在php中实现multipart / form-data和Heredoc？

0 个答案: