如何在Python中使用'*'打印三角形？

Question

赞：

          *
        * * *
      * * * * *
      ----n=5----

注意：n表示用户输入的是奇数整数。

Answer 1

将行号从0迭代到n / 2的上限，然后将行号居中两倍，再加上一颗星。

n = 5
for l in range(n//2+1):
    print(' '.join(['*'] * (l*2+1)).center(n*2))

给出：

    *     
  * * *   
* * * * * 

Answer 2

def asterisk_triangle(n):
    """
    takes an integer n and then returns an
    asterisk triangle consisting of (n) many columns
    """
    x = 1
    while (x <= (n+1)/2):
        space = int((n+1)/2-x)
        print(" " *space*2, end='')
        print("* " * (2*x-1))
        x = x + 1

    return

# call asterisk_triangle function here
# here n=9
asterisk_triangle(9)  

输出：

        * 
      * * * 
    * * * * * 
  * * * * * * * 
* * * * * * * * *