我已经为我的INSERT查询构建了一个DAO。代码:
DAO
public class EmployeeDao {
JdbcTemplate template;
public void setTemplate(JdbcTemplate template) {
this.template = template;
}
public int insert(EmployeeInfo emp){
String sql = "insert into employee VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)";
int i=template.update(sql, emp.getFirstName(), emp.getMiddleName(), emp.getLastName(), emp.getEmail(), emp.getGender(), emp.getDob(), emp.getAddress1(), emp.getAddress2(), emp.getEmpID());
return i;
}
}
控制器:
@Autowired
EmployeeDao dao;
@RequestMapping("/addresult")
public ModelAndView addResult(HttpServletRequest req,HttpServletResponse res) {
String fname = req.getParameter("FirstName");
String mname = req.getParameter("MiddleName");
String middlename;
if(mname!="null"&&mname.trim()!=""){
middlename=mname;
}
else
{
middlename="-";
}
String lname = req.getParameter("LastName");
//int empID = Integer.getInteger(req.getParameter("empID")).intValue();
String empid = req.getParameter("empID");
int empID = Integer.parseInt(empid);
String email = req.getParameter("Email");
String gender = req.getParameter("gender");
//Date dob = Date.valueOf(req.getParameter("DOB"));
LocalDate dob = LocalDate.parse(req.getParameter("DOB"));
String addr1 = req.getParameter("address1");
String addr2 = req.getParameter("address2");
EmployeeInfo emp = new EmployeeInfo(fname,middlename,lname,email,gender,dob,addr1,addr2,empID);
int ret = dao.insert(emp);
if(ret==0){
return new ModelAndView("EmployeeAddResult","mess","Success");
}
else
{
return new ModelAndView("EmployeeAddResult","mess","hi");
}
}
运行Web应用程序时,INSERT查询导致错误:
请求处理失败;嵌套异常为 org.springframework.jdbc.UncategorizedSQLException: PreparedStatementCallback; SQL的未分类SQLException [插入 放入员工VALUES中(?,?,?,?,?,?,?,?,?)]; SQL状态[XJ021]; 错误代码[20000];不支持类型。嵌套异常为 java.sql.SQLException:不支持类型。
此问题背后的原因是什么?
答案 0 :(得分:2)
您应使用java.sql.Date
而不是LocalDate
,并添加以下日期:
Date date = Date.valueOf(dob);