Question

我有2张这样的桌子：

表Student_Old：

id name city
1   A    X
2   B    Y
3   C    Z

表Student_new：

id name city
1   A    X
2   M    Y
3   C    K

如您所见，对于ID 2，名称在ID中不匹配，对于ID 3，城市在两个表中都不匹配（我正在对ID进行比较，ID是两个表中的主键，基本上student_new是old的备份表）。现在，我想获取这两个不匹配的行。例如： student_old s1，student_new s2-

s1.id  s2.id s1.name s2.name s1.city s2.city
  2      2       B      M      X       X
  3      3       C      C      Z       K

Answer 1

使用内部联接，where子句会过滤掉不匹配的名称和城市

select a.* , b.* from Student_Old inner join Student_new
on a.id=b.id
where a.name<>b.name or a.city<>b.city

Answer 2

使用加入

select os.*,ns.* Student_Old os join Student_new ns on os.id=ns.id 
where os.city!=ns.city OR os.name!=ns.name

Answer 3

SELECT so.id AS id_1, so.name AS name_1, so.city AS city_1,
sn.id AS id_2, sn.name AS name_2, sn.city AS city_2
FROM student_old so
INNER JOIN student_new sn
ON so.id = sn.id
WHERE so.name <> sn.name AND so.city <> sn.city

Answer 4

由于您不在乎一个表中的记录，而不在乎另一个表中的记录，因此简单的JOIN就足够了：

SELECT s1.id AS old_id, s2.id AS new_id,
       s1.name AS old_name, s2.name AS new_name,
       s1.city AS old_city, s2.city AS new_city
FROM student_old s1
JOIN student_new s2
ON s1.id = s2.id
WHERE s1.name != s2.name OR s1.city != s2.city

输出：

old_id  new_id  old_name    new_name    old_city    new_city
2       2       B           M           Y           Y
3       3       C           C           Z           K

查询以从两个表中选择不匹配的记录

4 个答案: