Question

解析JSON之后，我得到以下值：

myArray = "[63, 83, 87, 71]"

如何获取数组而不是字符串？我需要的是：

myArray = [63, 83, 87, 71]

更新：

这是我简单的json：

{
    "0": "[31,47,51]",
    "1": "[74, 47, 51, 78]",
    "2": "[72, 65, 69, 80]",
    "3": "[63, 83, 87, 71]"
}

这里是解析：

class gameModel: NSObject {
    func getCurrentArrays() -> NSDictionary {
        let appBundlePath:String? = Bundle.main.path(forResource: "testJsonPrepared", ofType: "json")

        if let actualBundlePath = appBundlePath {
            let urlPath:NSURL? = NSURL(fileURLWithPath: actualBundlePath)
            if let actualUrlPath = urlPath {
                let jsonData:NSData? = NSData(contentsOf: actualUrlPath as URL)
                if let actualJsonData = jsonData {
                    let dict: NSDictionary? = (try? JSONSerialization.jsonObject(with: actualJsonData as Data, options: JSONSerialization.ReadingOptions.mutableContainers)) as! NSDictionary?
                    if let currentArrays = dict {
                        return currentArrays
                    }
                }
            }
        }
        return NSDictionary()
    }
}

这是决赛：

class GameScene: SKScene {
    let model = gameModel()
    var arrays: NSDictionary = ["":""]

    override func didMove(to view: SKView) {
        arrays = model.getCurrentArrays()
        print("# func viewDidLoad arrays: \(arrays)")

        let testKey = String(3)

        let testArray = arrays.value(forKey: testKey) as! String
        print("# func viewDidLoad testArray: \(testArray)")
    }
}

===========

Update2谢谢，rmaddy。这是我的解决方案：

testJson.json

{
  "0": [31,47,51],
  "1": [74, 47, 51, 78],
  "2": [72, 65, 69, 80],
  "3": [63, 83, 87, 71]
 }

这是从json中读取的内容：

class GameScene: SKScene {



override func didMove(to view: SKView) {

    if let path = Bundle.main.path(forResource: "testJson", ofType: "json") {
        do {
            let data = try Data(contentsOf: URL(fileURLWithPath: path), options: .mappedIfSafe)
            let jsonResult = try JSONSerialization.jsonObject(with: data, options: .mutableLeaves)
            if let jsonResult = jsonResult as? Dictionary<String, [Int]>, let array = jsonResult["3"] {
                print("# func didMove array: \(array)")
            }
        } catch {
            // handle error
        }
      }
    }
 }

Answer 1

正如@Andy所提到的，数组值未以不正确的格式进行编码，因此被解码为字符串。格式应如下

 SQL> select * from employee;
            12 sachin                    48000         23
            13 raja                      49000         23
            35 vikas                     40000         26
            11 sau                       22000         24
            23 viru                      40000         26
            87 raju                       4500

如果您无法修复json，则应使用以下扩展名

{
    "0": [31,47,51],
    "1": [74, 47, 51, 78],
    "2": [72, 65, 69, 80],
    "3": [63, 83, 87, 71]
}

并按如下所示在ur arrayString上使用它

extension String{
    func toArray()->[Int]{
        var trimmedStr = self.replacingOccurrences(of: "[", with: "")
        trimmedStr = self.replacingOccurrences(of: "]", with: "")
        let strArray = trimmedStr.components(separatedBy: ",")
        return strArray.flatMap({Int($0)})

    }
}

获取数组而不是字符串

1 个答案: