Question

我在下面的查询中提取了我所有农民的表中的所有年龄段，但是我需要按性别类型分类的数据。

WITH AgeData as
(
  SELECT [sex],
         [dob],
         DATEDIFF(YEAR, [dob], GETDATE()) AS [AGE]
  FROM dbo.Farmers
),
GroupAge AS
(
  SELECT [sex],
         [dob],      
         CASE
             WHEN AGE < 24 THEN 'Under 24'
             WHEN AGE BETWEEN 25 AND 30 THEN '25 - 30'
             WHEN AGE BETWEEN 31 AND 40 THEN '31 - 40'
             WHEN AGE BETWEEN 41 AND 50 THEN '41 - 50'
             WHEN AGE > 50 THEN 'Over 50'
             ELSE 'Invalid Birthdate'
         END AS [Age Groups]
  FROM AgeData
)
SELECT COUNT(*) AS [AgeGrpCount],[Age Groups]
FROM GroupAge
GROUP BY [Age Groups];

如果将其添加到代码中，我会得到我的男性性别类型：

WITH AgeData as
(
  SELECT [sex],
         [dob],
         DATEDIFF(YEAR, [dob], GETDATE()) AS [AGE]
  FROM dbo.Farmers
),
GroupAge AS
(
  SELECT [sex],
         [dob],      
         CASE
             WHEN AGE < 24 THEN 'Under 24'
             WHEN AGE BETWEEN 25 AND 30 THEN '25 - 30'
             WHEN AGE BETWEEN 31 AND 40 THEN '31 - 40'
             WHEN AGE BETWEEN 41 AND 50 THEN '41 - 50'
             WHEN AGE > 50 THEN 'Over 50'
             ELSE 'Invalid Birthdate'
         END AS [Age Groups]
  FROM AgeData
)
SELECT COUNT(*) AS [MaleAgeGrpCount],[Age Groups]
FROM GroupAge
Where sex = 1
GROUP BY [Age Groups];

但是我想同时使用[MaleAgeGrpCount]和[FemaleAgeGrpCount] Colum，而其中sex = 1是男性，而sex = 2是女性。

Answer 1

使用条件聚合：

SELECT
    [Age Groups],
    COUNT(CASE WHEN sex = 1 THEN 1 END) AS [MaleAgeGrpCount],
    COUNT(CASE WHEN sex = 2 THEN 1 END) AS [FemaleAgeGrpCount]
FROM GroupAge
GROUP BY [Age Groups];

这里的想法是使用单独的CASE表达式来计算按年龄段汇总的男性和女性记录。

改善按性别查询结果

1 个答案: